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grandymaker [24]
3 years ago
11

Please help! This is due soon :(​

Mathematics
1 answer:
Papessa [141]3 years ago
8 0

Answer:

what grade us it maybe u can help you but if I cant I'm sorru

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The circumference of a circle is 60 pi cm. What is the length of an arc of 140 degrees
son4ous [18]
<span>circumference = 60*PI cm
If an arc is 140 degrees of the circle then its length =
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<span>60*PI cm * (140 / 360)
arc length = 23.33333 cm

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8 0
3 years ago
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Can anyone help me with this​
ss7ja [257]

Answer:

h

Step-by-step explanation:

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5 0
3 years ago
Find the m TFS.<br><br>Answer choices are:<br>12 degrees<br>76 degrees<br>64 degrees<br>52 degrees​
goblinko [34]
It’s 52 because there are two sides with 64 degrees (the bottom two sides) and you add those to sides together and subtract your combine angle of the bottom 2 sides by 180 degrees which is the degree of all triangles combine and get 52
4 0
3 years ago
Find the distance from the origin to the graph of 7x+9y+11=0
Cerrena [4.2K]
One way to do it is with calculus. The distance between any point (x,y)=\left(x,-\dfrac{7x+11}9\right) on the line to the origin is given by

d(x)=\sqrt{x^2+\left(-\dfrac{7x+11}9\right)^2}=\dfrac{\sqrt{130x^2+154x+121}}9

Now, both d(x) and d(x)^2 attain their respective extrema at the same critical points, so we can work with the latter and apply the derivative test to that.

d(x)^2=\dfrac{130x^2+154x+121}{81}\implies\dfrac{\mathrm dd(x)^2}{\mathrm dx}=\dfrac{260}{81}x+\dfrac{154}{81}

Solving for (d(x)^2)'=0, you find a critical point of x=-\dfrac{77}{130}.

Next, check the concavity of the squared distance to verify that a minimum occurs at this value. If the second derivative is positive, then the critical point is the site of a minimum.

You have

\dfrac{\mathrm d^2d(x)^2}{\mathrm dx^2}=\dfrac{260}{81}>0

so indeed, a minimum occurs at x=-\dfrac{77}{130}.

The minimum distance is then

d\left(-\dfrac{77}{130}\right)=\dfrac{11}{\sqrt{130}}
4 0
3 years ago
-9 + ( -16) =
Advocard [28]

Answer:

-9 + ( -16) = -25

( -4) – (-6) + (-5) – (8) =-11

( 3) – (-9) + (-3) – (-2) =11

- ( 5) – (-7) + (-8) =-6

- ( -8) – (-9) + (-4) – (-1) =14

( -5) – (-11) + (10) – (8) =8

( -1) – (-2) + (-3) – (-6) =4

( -4) – ( 4) – (6) + (-5) – (-8) =-11

(-6) + (-5) – (-8) =-3

Step-by-step explanation:

Hope it helps

6 0
3 years ago
Read 2 more answers
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