Please help! This is due soon :(
1 answer:
You might be interested in
If you have two vectors A and B,
Dot product is a scalar quantity dealing with how much of one vector is in the same direction as the other vector, or the projection of one onto the other. You can see that from the cosine part of this form-
![A~*~B = [A][B]cos(\theta)](https://tex.z-dn.net/?f=A~%2A~B%20%3D%20%5BA%5D%5BB%5Dcos%28%5Ctheta%29)
The cross product is a vector perpendicular to both A and B. It deals with how much of one vector is perpendicular to the other vector. You can see that in the sine part of this form -
![A ~x ~B= [A][B]sin(\theta)](https://tex.z-dn.net/?f=A%20~x%20~B%3D%20%5BA%5D%5BB%5Dsin%28%5Ctheta%29)
Dot product is a scalar quantity dealing with how much of one vector is in the same direction as the other vector, or the projection of one onto the other. You can see that from the cosine part of this form-
The cross product is a vector perpendicular to both A and B. It deals with how much of one vector is perpendicular to the other vector. You can see that in the sine part of this form -
Answer:
a)
b)Step-by-step explanation:
Previous concepts
The Chi Square distribution is the distribution of the sum of squared standard normal deviates .
For this case we assume that the sample variance is given by and we select a random sample of size n from a normal population with a population variance
. And we define the following statistic:
And the distribution for this statistic is
For this case we know that n =25 and so then our statistic would be given by:
With 25-1 =24 degrees of freedom.
Solution to the problem
Part a
For this case we want this probability:
And we can multiply the inequality by 4 on both sides and we got:
And we can use the following excel code to find it: "=1-CHISQ.DIST(36.4,24,TRUE)"
Part b
For this case we want this probability:
If we multiply the inequality by 4 on all the terms we got:
And we can find this probability like this:
And we use the following code to find the answer in excel: "=CHISQ.DIST(42.98,24,TRUE)-CHISQ.DIST(13.848,24,TRUE)"