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amid [387]
3 years ago
12

Divide. Write your answer as a decimal. 0.459 divided by 0.17 =

Mathematics
2 answers:
alexandr402 [8]3 years ago
5 0

Answer:

2.7

Step-by-step explanation:

0.459÷0.17=2.7

here is your answer!

Rudik [331]3 years ago
4 0

Answer:

0.459 divided by 0.17 equals 2.7

Step-by-step explanation:

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Can you please help me answer this picture​
amid [387]

Answer:

C

Step-by-step explanation:

A solution is where the line touches the x-axis, and the line touches 4 and 8, which means 4 and 8 are the two solutions.

4 0
3 years ago
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The numbers 45 28 53 form a pythagorean triple true or false
GarryVolchara [31]
You can verify this by plugging the numbers into the Pythagorean theorem, a^2+b^2=c^2, where c is the hypotenuse (the longest side, in this case 53).

So it would be: 28^2 + 45^2 = 53^2
The equation is true.
2809 = 2809

5 0
3 years ago
Which point could be used to find f(-3)
Naddik [55]

Point C.

f(-3) is basically substituting x = -3 and get the y-value.

So when we substitute x = -3. Focus on x-axis at x = -3 then look up for the y-value. If the y-value is on x = -3 then that's f(-3)

3 0
3 years ago
Can anyone help me with this math question
Karolina [17]

Answer:

Dan made more money last month

Step-by-step explanation:

15/100   10/100 Make the Percent's into decimal's and Dan's is still higher

6 0
3 years ago
A city planner wants to estimate, with a 99% confidence level, the average monthly residential water usage in the city. Based on
torisob [31]

Answer: 82

Step-by-step explanation:

The formula to find the sample size is given by :-

n= (\dfrac{z^*\cdot \sigma}{E})^2

, where E = Margin of error.

\sigma = Population standard deviation for the prior study.

As per given , we have

\sigma=387.40 gallons.

Margin of error : E= 110 gallons

Critical value for 99% confidence level = z* = 2.576

Then, the required sample size : n= (\dfrac{(2.576)\cdot (387.40)}{110})^2

n= (9.07220363636)^2\approx82  {Rounded to the nearest integer.}

Hence, the minimum sample size = 82

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3 years ago
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