p = (1/r) - q
In order to find this, follow the order of operations to get the answer.
1/p+q = r ----> Multiply both sides by p+q
1 = r(p + q) -----> Divide by r
1/r = p + q -----> subtract q from both sides
(1/r) - q = p
For domain 2x sqrt(2+x)>0
x>0,2+x>0,x>-2 combining
we get x>2
f'(x)=[1/{2x sqrt(2+x)}][{2x/(2 sqrt(2+x))}+2 sqrt(2+x)]
Its perpendicular, if you need me to explain lmk
Step-by-step explanation:
everything can be found in the picture