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3 years ago

YOU WILL GET 100 PTS IF YOU ANSWER MY QUESTION CORRECTLY :D

Mathematics

1 answer:

Leokris [45]3 years ago

8 0

Answer: B seems to be the correct one

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Solve h for -9h-15=93

Lerok [7]

The answer to this question:

h=-12

8 0

3 years ago

150 - 1/2s = 120 + 1/4s

agasfer [191]

Answer:

s=40

Step-by-step explanation:

Combine s and 1/2.

150−s/2=120+1/4s

Combine 1/4and s.

150−s/2=120+s/4

Move all terms containing s to the left side of the equation.

150−3s/4=120

Move all terms not containing s to the right side of the equation.

−3s/4=−30

Multiply both sides of the equation by −4/3.

−4/3 x (−3s/4)=−4/3 x−30 => S=40

3 0

3 years ago

Read 2 more answers

Caroline earns $54 for 6 hours of babysitting. What is Caroline's rate in dollars per hour?

Elena L [17]

Answer:

Divided 54 divided by 6 = 9

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Calculus 2

FinnZ [79.3K]

Answer:

See Below.

Step-by-step explanation:

We want to estimate the definite integral:

$\displaystyle \int_1^47\sqrt{\ln(x)}\, dx$

Using the Trapezoidal Rule, Midpoint Rule, and Simpson's Rule with six equal subdivisions.

The trapezoidal rule is given by:

$\displaystyle \int_{a}^bf(x)\, dx\approx\frac{\Delta x}{2}\Big(f(x_0)+2f(x_1)+...+2f(x_{n-1})+f(x_n)\Big)$

Our limits of integration are from x = 1 to x = 4. With six equal subdivisions, each subdivision will measure:

$\displaystyle \Delta x=\frac{4-1}{6}=\frac{1}{2}$

Therefore, the trapezoidal approximation is:

$\displaystyle =\frac{1/2}{2}\Big(f(1)+2f(1.5)+2f(2)+2f(2.5)+2f(3)+2f(3.5)+2f(4)\Big)$

Evaluate:

$\displaystyle =\frac{1}{4}(7)(\sqrt{\ln(1)}+2\sqrt{\ln(1.5)}+...+2\sqrt{\ln(3.5)}+\sqrt{\ln(4)})\\\\\approx18.139337$

The midpoint rule is given by:

$\displaystyle \int_a^bf(x)\, dx\approx\sum_{i=1}^nf\Big(\frac{x_{i-1}+x_i}{2}\Big)\Delta x$

Thus:

$\displaystyle =\frac{1}{2}\Big(f\Big(\frac{1+1.5}{2}\Big)+f\Big(\frac{1.5+2}{2}\Big)+...+f\Big(\frac{3+3.5}{2}\Big)+f\Big(\frac{3.5+4}{2}\Big)\Big)$

Simplify:

$\displaystyle =\frac{1}{2}(7)\Big(f(1.25)+f(1.75)+...+f(3.25)+f(3.75)\Big)\\\\ =\frac{1}{2}(7) (\sqrt{\ln(1.25)}+\sqrt{\ln(1.75)}+...+\sqrt{\ln(3.25)}+\sqrt{\ln(3.75)})\\\\\approx 18.767319$

Simpson's Rule is given by:

$\displaystyle \int_a^b f(x)\, dx\approx\frac{\Delta x}{3}\Big(f(x_0)+4f(x_1)+2f(x_2)+4f(x_3)+...+4f(x_{n-1})+f(x_n)\Big)$

So:

$\displaystyle =\frac{1/2}{3}\Big((f(1)+4f(1.5)+2f(2)+4f(2.5)+...+4f(3.5)+f(4)\Big)$

Simplify:

$\displaystyle =\frac{1}{6}(7)(\sqrt{\ln(1)}+4\sqrt{\ln(1.5)}+2\sqrt{\ln(2)}+4\sqrt{\ln(2.5)}+...+4\sqrt{\ln(3.5)}+\sqrt{\ln(4)})\\\\\approx 18.423834$

6 0

3 years ago

PLEASE HELP ASAP WILL GIVE BRAINLEIST

OleMash [197]

Angle Q and angle S equal 61

6 0

3 years ago