Answer:
0.294
Step-by-step explanation:
The number of possible outcomes for 2 consecutive days is 2 (Friday, Saturday and Saturday,Sunday).
Prob( Friday, Saturday has rain) = 0.70*0.70* 0.30) = 0.147 (No rain Sunday)
Prob( Saturday/Sunday has rain) = 0.30*0.70*0.7) = 0.147 (No rain Friday)
Required Probability = 2*0.147
= 0.294.
the lenght of the picture is 14
Solution:
The three powers whose value is greater than 500 and less than 550 can be find by following procedure.
We will solve this problem by Hit and trial method by finding the squares, cubes, fourth power, Fifth Power,...etc. of different natural numbers.
23²= 529
8³ = 8 × 8 × 8 =512
The three powers are →→→Eighth power of 2, Square of 23, and Cube of 8.
First term ,a=4 , common difference =4-7=-3, n =50
sum of first 50terms= (50/2)[2×4+(50-1)(-3)]
=25×[8+49]×-3
=25×57×-3
=25× -171
= -42925
derivation of the formula for the sum of n terms
Progression, S
S=a1+a2+a3+a4+...+an
S=a1+(a1+d)+(a1+2d)+(a1+3d)+...+[a1+(n−1)d] → Equation (1)
S=an+an−1+an−2+an−3+...+a1
S=an+(an−d)+(an−2d)+(an−3d)+...+[an−(n−1)d] → Equation (2)
Add Equations (1) and (2)
2S=(a1+an)+(a1+an)+(a1+an)+(a1+an)+...+(a1+an)
2S=n(a1+an)
S=n/2(a1+an)
Substitute an = a1 + (n - 1)d to the above equation, we have
S=n/2{a1+[a1+(n−1)d]}
S=n/2[2a1+(n−1)d]
