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vagabundo [1.1K]
2 years ago
5

help pls ill give extra points !:)

Mathematics
2 answers:
schepotkina [342]2 years ago
7 0
The second choice :D
makkiz [27]2 years ago
4 0

Answer:

X rc/2

Hope I helped u

Step-by-step explanation:

¶Emma Jews

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Given that the measure of ∠x is 60°, and the measure of ∠y is 90°, find the measure of ∠z.
UkoKoshka [18]
The answer is 30 because u need to add 60+90=150 and then subtract 180-150 which gives you 30
7 0
3 years ago
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Graph the line with 1/2 slope<br> passing through the point (-5,1).
Ghella [55]

Answer:

Go on dezmos it will do it for you if you just wright the coordinates in

Step-by-step explanation:

5 0
3 years ago
The number of bacteria in a refrigerated food product is given by N ( T ) = 22 T 2 − 123 T + 40 , 6 &lt; T &lt; 36 , where T is
antoniya [11.8K]

Answer:

N(T(t)) = 1408t^2 - 385.6t - 105.52

Time for bacteria count reaching 8019: t = 2.543 hours

Step-by-step explanation:

To find the composite function N(T(t)), we just need to use the value of T(t) for each T in the function N(T). So we have that:

N(T(t)) = 22 * (8t + 1.7)^2  - 123 * (8t + 1.7) + 40

N(T(t)) = 22 * (64t^2 + 27.2t + 2.89) - 984t - 209.1 + 40

N(T(t)) = 1408t^2 + 598.4t + 63.58 -  984t - 169.1

N(T(t)) = 1408t^2 - 385.6t - 105.52

Now, to find the time when the bacteria count reaches 8019, we just need to use N(T(t)) = 8019 and then find the value of t:

8019 = 1408t^2 - 385.6t - 105.52

1408t^2 - 385.6t - 8124.52 = 0

Solving this quadratic equation, we have that t = 2.543 hours, so that is the time needed to the bacteria count reaching 8019.

4 0
3 years ago
Are the expressions 12a + (6+3a) and 3(5a + 2) equivalent show your work and explain
bezimeni [28]
12a + 6 + 3a = 15a + 2
15a = 15a - 4
0 = - 4
8 0
2 years ago
Read 2 more answers
What is the equation of a line that passes through the point (1, 8) and is perpendicular to the line whose equation is y=x/2+3 ?
Svet_ta [14]

<u>Answer</u>

y = -2x + 10


<u>Explanation</u>

The general equation for a straight line is y = mx + c where m and c are gradient and y-intercept respectively.

y=x/2+3 = y (1/2)x + 3

gradient = 1/2

Gradient of the line perpendicular to y=x/2+3 is;

m × 1/2 = -1

m = -2

Now we find the equation of a line passing through (1,8) and have a gradient of -2.

-2 = (y - 8)/(x - 1)

-2(x - 1) = (y - 8)

2 -2x = y - 8

y = -2x + 10


3 0
3 years ago
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