All categories

3 years ago

What is the value of x 55,105 A.50 B.20 C.160 D.55

Mathematics

1 answer:

Ann [662]3 years ago

7 0

Answer:

c)55

Step-by-step explanation:

You might be interested in

1kg costs £1.28. what is the cost of 250g

vivado [14]

First, convert 1 kg to g.

1 kg = 1000 g

So 1000 g = 1.28

Set up a proportion:

1000/1.28 = 250/x

Cross multiply:

1000x = 320

Divide 1000 to both sides:

x = 0.32

So 250g costs £0.32

8 0

3 years ago

Could you help me to solve the problem below the cost for producing x items is 50x+300 and the revenue for selling x items is 90

s344n2d4d5 [400]

Answer:

Profit function: P(x) = -0.5x^2 + 40x - 300

profit of $50: x = 10 and x = 70

NOT possible to make a profit of $2,500, because maximum profit is $500

Step-by-step explanation:

(Assuming the correct revenue function is 90x−0.5x^2)

The cost function is given by:

$C(x) = 50x + 300$

And the revenue function is given by:

$R(x) = 90x - 0.5x^2$

The profit function is given by the revenue minus the cost, so we have:

$P(x) = R(x) - C(x)$

$P(x) = 90x - 0.5x^2 - 50x - 300$

$P(x) = -0.5x^2 + 40x - 300$

To find the points where the profit is $50, we use P(x) = 50 and then find the values of x:

$50 = -0.5x^2 + 40x - 300$

$-0.5x^2 + 40x - 350 = 0$

$x^2 - 80x + 700 = 0$

Using Bhaskara's formula, we have:

$\Delta = b^2 - 4ac = (-80)^2 - 4*700 = 3600$

$x_1 = (-b + \sqrt{\Delta})/2a = (80 + 60)/2 = 70$

$x_2 = (-b - \sqrt{\Delta})/2a = (80 - 60)/2 = 10$

So the values of x that give a profit of $50 are x = 10 and x = 70

To find if it's possible to make a profit of $2,500, we need to find the maximum profit, that is, the maximum of the function P(x).

The maximum value of P(x) is in the vertex. The x-coordinate of the vertex is given by:

$x_v = -b/2a = 80/2 = 40$

Using this value of x, we can find the maximum profit:

$P(40) = -0.5(40)^2 + 40*40 - 300 = $500$

The maximum profit is $500, so it is NOT possible to make a profit of $2,500.

3 0

3 years ago

How much dextrose is contained within 200mL of D5W?

Mumz [18]

Answer:

10 grams in 200ml because for 100ml is 5 grams

Step-by-step explanation:

4 0

2 years ago

46225 find squre root

Margarita [4]

Square root means 46225^1/2 so the answer is 65

4 0

3 years ago

Read 2 more answers

What is the Laplace Transform of 7t^3 using the definition (and not the shortcut method)

Leokris [45]

Answer:

Step-by-step explanation:

By definition of Laplace transform we have

L{f(t)} = $L{{f(t)}}=\int_{0}^{\infty }e^{-st}f(t)dt\\\\Given\\f(t)=7t^{3}\\\\\therefore L[7t^{3}]=\int_{0}^{\infty }e^{-st}7t^{3}dt\\\\$

Now to solve the integral on the right hand side we shall use Integration by parts Taking $7t^{3}$ as first function thus we have

$\int_{0}^{\infty }e^{-st}7t^{3}dt=7\int_{0}^{\infty }e^{-st}t^{3}dt\\\\= [t^3\int e^{-st} ]_{0}^{\infty}-\int_{0}^{\infty }[(3t^2)\int e^{-st}dt]dt\\\\=0-\int_{0}^{\infty }\frac{3t^{2}}{-s}e^{-st}dt\\\\=\int_{0}^{\infty }\frac{3t^{2}}{s}e^{-st}dt\\\\$

Again repeating the same procedure we get

$=0-\int_{0}^{\infty }\frac{3t^{2}}{-s}e^{-st}dt\\\\=\int_{0}^{\infty }\frac{3t^{2}}{s}e^{-st}dt\\\\\int_{0}^{\infty }\frac{3t^{2}}{s}e^{-st}dt= \frac{3}{s}[t^2\int e^{-st} ]_{0}^{\infty}-\int_{0}^{\infty }[(t^2)\int e^{-st}dt]dt\\\\=\frac{3}{s}[0-\int_{0}^{\infty }\frac{2t^{1}}{-s}e^{-st}dt]\\\\=\frac{3\times 2}{s^{2}}[\int_{0}^{\infty }te^{-st}dt]\\\\$

Again repeating the same procedure we get

$\frac{3\times 2}{s^2}[\int_{0}^{\infty }te^{-st}dt]= \frac{3\times 2}{s^{2}}[t\int e^{-st} ]_{0}^{\infty}-\int_{0}^{\infty }[(t)\int e^{-st}dt]dt\\\\=\frac{3\times 2}{s^2}[0-\int_{0}^{\infty }\frac{1}{-s}e^{-st}dt]\\\\=\frac{3\times 2}{s^{3}}[\int_{0}^{\infty }e^{-st}dt]\\\\$

Now solving this integral we have

$\int_{0}^{\infty }e^{-st}dt=\frac{1}{-s}[\frac{1}{e^\infty }-\frac{1}{1}]\\\\\int_{0}^{\infty }e^{-st}dt=\frac{1}{s}$

Thus we have

$L[7t^{3}]=\frac{7\times 3\times 2}{s^4}$

where s is any complex parameter

5 0

3 years ago