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posledela
2 years ago
13

Can someone please help me with this question?? (no links!!!)

Mathematics
2 answers:
omeli [17]2 years ago
8 0

Answer:

960

Step-by-step explanation:

it says use 3 for pi, so you plug the values into given equation

V = 3·(4)²·20

r is 4 because it is half of 8.

Then multiply

3·16·20 = 48·20 = 960

Kamila [148]2 years ago
6 0

Answer:

960 cm

Step-by-step explanation:

8/2 = 4 (radius)

3 (since we're using 3 for pi) * 4^2 * 20

3 * 16 * 20

48 * 20

= 960 cm

I hope this helps heh :)

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harry buys 22 fish he has a round fish bowl and a rectangular fish tank how could he place the fish in the bowl and tank
Lana71 [14]

Answer: put 11 in each one


Step-by-step explanation:


6 0
2 years ago
Help with math problem​
trasher [3.6K]

Answer:

1.No- that just means that the numbers on that side are smaller

Step-by-step explanation:

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3 years ago
A 5-card hand is dealt from a perfectly shuffled deck. Define the events: A: the hand is a four of a kind (all four cards of one
TiliK225 [7]

In a hand of 5 cards, you want 4 of them to be of the same rank, and the fifth can be any of the remaining 48 cards. So if the rank of the 4-of-a-kind is fixed, there are \binom44\binom{48}1=48 possible hands. To account for any choice of rank, we choose 1 of the 13 possible ranks and multiply this count by \binom{13}1=13. So there are 624 possible hands containing a 4-of-a-kind. Hence A occurs with probability

\dfrac{\binom{13}1\binom44\binom{48}1}{\binom{52}5}=\dfrac{624}{2,598,960}\approx0.00024

There are 4 aces in the deck. If exactly 1 occurs in the hand, the remaining 4 cards can be any of the remaining 48 non-ace cards, contributing \binom41\binom{48}4=778,320 possible hands. Exactly 2 aces are drawn in \binom42\binom{48}3=103,776 hands. And so on. This gives a total of

\displaystyle\sum_{a=1}^4\binom4a\binom{48}{5-a}=886,656

possible hands containing at least 1 ace, and hence B occurs with probability

\dfrac{\sum\limits_{a=1}^4\binom4a\binom{48}{5-a}}{\binom{52}5}=\dfrac{18,472}{54,145}\approx0.3412

The product of these probability is approximately 0.000082.

A and B are independent if the probability of both events occurring simultaneously is the same as the above probability, i.e. P(A\cap B)=P(A)P(B). This happens if

  • the hand has 4 aces and 1 non-ace, or
  • the hand has a non-ace 4-of-a-kind and 1 ace

The above "sub-events" are mutually exclusive and share no overlap. There are 48 possible non-aces to choose from, so the first sub-event consists of 48 possible hands. There are 12 non-ace 4-of-a-kinds and 4 choices of ace for the fifth card, so the second sub-event has a total of 12*4 = 48 possible hands. So A\cap B consists of 96 possible hands, which occurs with probability

\dfrac{96}{\binom{52}5}\approx0.0000369

and so the events A and B are NOT independent.

4 0
3 years ago
It is 2.8km from David’s house to the nearest mailbox. How far is it in meters?
Ganezh [65]

Solution

Distance in km = 2.8 km

Distance in m = 2.8 x 1000m

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5 0
10 months ago
Sophie can type 128 words in 3 minutes. How many minutes will it take her to type 576 words?​
Andrej [43]
Let’s first find the rate that she types at in wok.
128/3 = 42+2/3 words per minute.
Now divide 576 by the rate.
576/42.666= 13.5 minutes
7 0
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