The interquartile range (IQR) can be found by finding the difference of the upper and lower quartiles
Answer:
Tim has 64 dollars. I did the math and I know I'm right
Answer:
A AND B IS TRUE C IS FALSE
Step-by-step explanation:
Answer:
{1, 5, 25, 125, 625}
Step-by-step explanation:
The smallest positive integers that meet the requirement will be ...
5^0 = 1
5^1 = 5
5^2 = 25
5^3 = 125
5^4 = 625
As a set, these numbers are {1, 5, 25, 125, 625}.
The correct quadratic equation;
x2+7x-2=0
Working
Assuming the frame has a uniform thickness;
Then length of mirror and frame is 3+x and width 2+x
The area of mirror and frame area;
A=L*W
8=(3+x)(2+x)
8=(6+5x+x2)
Taking 8 to the Right hand side, we have:
x2+5x-2 =0
