Question

The total sales of a company (in millions of dollars) t months from now are given by S(t) = 0.03t3 + 0.5t2 + 9t + 4. Find S'(t). Find S(2) and S'(2) (to two decimal places). Interpret S(11) = 203.43 and S'(11) = 30.89

Answer 1

Answer:

S'(t) = 0.09t^2 + t + 9

S(2) = 24.24

S'(2) = 11.36

S(11) = 203.43 means that the sales of the company 11 months from now is $203,430,000.

S'(11) = 30.89 means that, 11 months from now, the rate at which sales change is $30,890,000 per month

Step-by-step explanation:

The derivate of the sales function S'(t) , which is the rate at which sales vary with time in months, is:

$\frac{dS(t)}{dt} =S'(t) = 0.09t^2 + t + 9$

S(2) is found by applying t=2 to S(t):

$S(2) = 0.03*(2^3) + 0.5*(2^2) + 9*2 + 4\\S(2)= 24.24$

S'(2) is found by applying t=2 to S'(t):

$S'(2) = 0.09*(2^2) + 2 + 9\\S'(2) = 11.36$

Since the sales function gives the amount of sales in millions of dollars,

S(11) = 203.43 means that the sales of the company 11 months from now is $203,430,000.

S'(t) represents the rate of change in sales in millions of dollars per month.

S'(11) = 30.89 means that, 11 months from now, the rate at which sales change is $30,890,000 per month