The electric field strength at any point from a charged particle is given by E = kq/r^2 and we can use this to calculate the field strength of the two fields individually at the midpoint.
The field strength at midway (r = 0.171/2 = 0.0885 m) for particle 1 is E = (8.99x10^9)(-1* 10^-7)/(0.0885)^2 = -7.041 N/C and the field strength at midway for particle 2 is E = (8.99x10^9)(5.98* 10^-7)/(0.0935)^2 = <span>-7.041 N/C
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Note the sign of the field for particle 1 is negative so this is attractive for a test charge whereas for particle 2 it is positive therefore their equal magnitudes will add to give the magnitude of the net field, 2*<span>7.041 N/C </span>= 14.082 N/C
Answer:
5,184•b•t^6/5
Step-by-step explanation:
Here, we want to multiply the expressions
According to indices law, if we have same bases, we add up the exponents
Thus, we have that;
8 *8b^(2/3+5/3) * 9 * 9 * t^(3/5+3/5)
= 64 * b * 81 * t^6/5
= 5,184bt^6/5
Tuesday.
1/2 =50%, 3/4=75% 2/3=66.6% and so forth.
Answer:
Increase by $145
Step-by-step explanation:
= $ (x + 145 + 145)
= $ (x + 290)
108
Step-by-step explanation:
because you would have to take the width times the height and that is 52 times 4
