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Gnoma [55]
3 years ago
12

How many hours would it take to get from Miami FL to New Hampshire?

Mathematics
1 answer:
bonufazy [111]3 years ago
8 0
It would most likely take 3-4 hours, maybe even 5.
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It is estimated that there are approximately 1 × 1014 cells in the human body. Which of the following represents this amount in
serg [7]
1014 hope thts the awnser it seemed to obvious
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3 years ago
Pls answer picture is below
ahrayia [7]
Mass, hardness, density, luster
3 0
3 years ago
100 BRAINLY POINTS!!!
BARSIC [14]

Answer:

C)   y=-0.5x+8

Step-by-step explanation:

Line of best fit (trendline) : a line through a scatter plot of data points that best expresses the relationship between those points.

All the given options for the line of best fit are linear equations.

Therefore, we can add the line of best fit to the graph (see attached), remembering to have roughly the same number of points above and below the line.

Linear equation:  y=mx+b

(where m is the slope and b is the y-intercept)

From inspection of the line of best fit, we can see that the y-intercept (where x = 0) is approximately 8.  So this suggests that options C or D are the solution.

We can also see that the slope (gradient) of the line of best fit is approximately -0.5 (as the rate of change (y/x) is -1 unit of y for every +2 units of x).

Therefore, C is the solution, and the closet approximation to the line of best fit is y=-0.5x+8

4 0
2 years ago
Please help! How on earth do I do this? In the year 2015, Anna bought a new car for $36,000. In 2017, she was told that the valu
Klio2033 [76]

Part A

Purchase Value of Anna's Car in 2015 = $36,000

Depreciated Value of Anna's Car in 2017 = $25,000

We know that the value of the car is depreciating linearly.


From the above data, we can see that the value of the car has reduced by $36,000-$25,000 = $11,000 over 2 years.

⇒ Per year the value has been depreciated by \frac{11000}{2}

⇒ Per year the value has been depreciated by $5,500

So if the value of a car in 2015 is V₀ then value of the car after t years can be determined by the below function:

V (t) = V₀ - (t*5,500), where t indicates the years passed since 2015

OR V (t) = 36,000 - (t*5,500), where t indicates the years passed since 2015

Part B

Suggested value of Anna's car for trade in option in 2018 = $15,000

In 2018, 3 years would have been passed since 2015. Using the value of t = 3 in the function determined in Part A:

V(3) = V₀ - (3*5,500)

⇒ V(3) = 36,000 - (16,500)

⇒ V(3) = $19,000

From the above calculations, we can see that the value of the car in 2018 should be $19,000, however the suggested value for trade in is indicated as $15,000 which is lower than what the value of the car should be. Hence, basis linear depreciation, the $15,000 value is not fair for the car in 2018.

3 0
3 years ago
Carol is making a pattern with toothpicks. The first five terms of Carol's pattern are shown.
stellarik [79]

Answer:

B

Step-by-step explanation:

Let's make a table:

Term 1:     3 toothpicks

Term 2:     4 toothpicks

Term 3:     5 toothpicks

Term 4:     6 toothpicks

Term 5:     7 toothpicks

Term N = N + 2 toothpicks

6 0
3 years ago
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