There are 10 letters in the set {a, b, c, d, e, f, g, h, i, j} which is the pool of letters to choose from when making these three letter codes.
We have 10 choices for slot 1
Then 9 choices for slot 2. This is because we can't reuse the choice for slot 1
Then 8 choices for slot 3
Overall, there are 10*9*8 = 90*8 = 720 different permutations
Answer: 720
Note: you can use the nPr permutation formula with n = 10 and r = 3 to get the same answer
Answer:
B
Step-by-step explanation:
V = 4/3 * radius^3 * pi = 4/3 * 4^3 * pi = 256 /3 * pi
Intersect at where x=x and y=y
see where they have the same x and y values
that is at x=-1 and y=-5
intersect at (-1,-5)
Answer:
Lee has 19 nickels and 8 dimes
Step-by-step explanation:
hello, I think I can help you with this
Step 1
Let
value of a nickel=$0.05
value of a dime=$0.10
number of nickels=N
number of nickels=D
According to the question data Lee has $1.75 in dimes and nickels.
0.05N+0.1D=1.75,equation(1)
also, the number of nickels is 11 more than the number of dimes.mathematical speaking
N=11+D,equation(2)
Step 2
replace N from equation (2) into equation (1)
0.05N+0.1D=1.75
0.05(11+D)+0.1D=1.75
Now, solve for D
0.55+0.05D+0.1D=1.75
0.15D=1.75-0.55
D=1.2/0.15
D=8
Step 3
replace the value of D into equation(2) to obtain N
N=11+8
N=11+8
N=19
Hence, Lee has 19 nickels and 8 dimes
Have a great day.
