We have the following expression:
y = logbx
We clear x of the expression.
We have then:
b ^ y = b ^ (logbx)
Rewriting:
x = b ^ y
Substituting we have:
x = b ^ 0
x = 1
Answer:
If (x, 0) lies on the graph of y = logbx, then:
x = 1
The quadratic formula is:
(-b ± √b² - 4ac)/2a
So first we need to find what a, b, and c are by making the equation equal to 0.
We can do this by adding 13x and subtracting 10 to get -7x² + 13x - 10, so your values would be a = -7, b = 13, and c = -10.
Now you can just substitute them into the equation:
(-13 ± √13² - 4 × -7 × -10)/-14
I believe that is your answer in standard form, so I hope this helps!
Answer:5.25
Step-by-step explanation:
(7/8 of a mile) x (6 days)
Answer:
18 inc wide is the qnswer