Answer: A
Step-by-step explanation:
Take the point (0, -6). The floor of 0 is 0, so normally it would be (0, 0). However, since the y coordinate is -6, not 0, we know it was translated down 6 units. Therefore, the answer is A.
0<x<1 and 0<y<1
x>0 so x is positive and y>0 so y is also positive.
When you multiply two positive numbers you always get a positive number, so the product of x and y must be positive, or greater than 0.
xy>0 - it must be true
xy<0 - it can't be true
Also when you divide a positive number by a positive number you always get a positive number, so the quotient of x and y must be positive.
x/y<0 - it can't be true
D and E can be true, but don't have to. It depends on the values of x and y. If x>y, then x-y>0 is true and x-y<0 isn't true; if x<y, then x-y>0 isn't true and x-y<0 is true.
Therefore, only A <u>must</u> be true.
1. 32 cents
2.im not sure
Answer:
(sqrt(7))/3 or decimal 0.8819171036881968635005385845464201419034197276941500601227781530...
Step-by-step explanation:
Simplify the following:
(sqrt(14))/(sqrt(18))
Hint: | Simplify radicals.
sqrt(18) = sqrt(2×3^2) = 3 sqrt(2):
(sqrt(14))/(3 sqrt(2))
Hint: | Multiply numerator and denominator of (sqrt(14))/(3 sqrt(2)) by sqrt(2).
Rationalize the denominator. (sqrt(14))/(3 sqrt(2)) = (sqrt(14))/(3 sqrt(2))×(sqrt(2))/(sqrt(2)) = (sqrt(14) sqrt(2))/(3×2):
(sqrt(14) sqrt(2))/(3×2)
Hint: | Multiply 3 and 2 together.
3×2 = 6:
(sqrt(14) sqrt(2))/6
Hint: | For a>=0, sqrt(a) sqrt(b) = sqrt(a b). Apply this to sqrt(14) sqrt(2).
sqrt(14) sqrt(2) = sqrt(14×2):
(sqrt(14×2))/6
Hint: | Multiply 14 and 2 together.
14×2 = 28:
(sqrt(28))/6
Hint: | Simplify radicals.
sqrt(28) = sqrt(2^2×7) = 2 sqrt(7):
(2 sqrt(7))/6
Hint: | In (2 sqrt(7))/6, divide 6 in the denominator by 2 in the numerator.
2/6 = 2/(2×3) = 1/3:
Answer: (sqrt(7))/3
Answer:
C; right answer on Khan Academy
Step-by-step explanation:
