2.25x=27<br> Addition Property <br> Substraction Property

Danny is measuring rainfalll.For a.Science project in september 7/8 inch of rain fell in october 2 1/4 invhes of rain fell how m

horsena [70]

Answer: $1\dfrac{3}{8}\ \text{inch}$

Step-by-step explanation:

Given

Rainfall in September is $\frac{7}{8}$ inch

Rainfall in October is $2\frac{1}{4}$ inch

Convert mixed fraction into fraction

$\Rightarrow 2\dfrac{1}{4}=\dfrac{9}{4}\ \text{inch}$

Difference between the two gives that how much more rain fall in October compared to September

$\Rightarrow \dfrac{9}{4}-\dfrac{7}{8}\\\\\Rightarrow \dfrac{18-7}{8}\\\\\Rightarrow \dfrac{11}{8}\ \text{inch or}\\\\\Rightarrow 1\dfrac{3}{8}\ \text{inch}$

3 0

3 years ago

These tables represent a quadratic function with a vertex at (0, 3). What is the

astra-53 [7]

The answer is d . -97

7 0

2 years ago

Please help me!!!!!!!!!!!

solmaris [256]

Answer:

Step-by-step explanation:

5 0

3 years ago

A random sample of 100 people was taken. Eighty-five of the people in the sample favored Candidate A. We are interested in deter

lbvjy [14]

Answer:

$z=\frac{0.85 -0.8}{\sqrt{\frac{0.8(1-0.8)}{100}}}=1.25$

$p_v =P(z>1.25)=0.106$

If we compare the p value obtained and the significance level given $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of people who favored candidate A is not significalty higher than 0.8

ii) not significantly greater than 80%

Step-by-step explanation:

Data given and notation

n=100 represent the random sample taken

$\hat p=0.85$ estimated proportion of people who favored candidate A

$p_o=0.8$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion is higher than 0.8.:

Null hypothesis: $p\leq 0.8$

Alternative hypothesis: $p > 0.8$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.85 -0.8}{\sqrt{\frac{0.8(1-0.8)}{100}}}=1.25$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(z>1.25)=0.106$

If we compare the p value obtained and the significance level given $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of people who favored candidate A is not significalty higher than 0.8

ii) not significantly greater than 80%

8 0

3 years ago

What is the value of x to the nearest tenth?

Alex_Xolod [135]

Hi there!

In order to solve for x, we'll need to use a trigonometry ratio. In this case, we'll use tangent, which is opposite over adjacent.

Here is our equation:
tan(37)/1 = x/2.1

Cross-Multiply:
x = tan(37) * 2.1

Solve:
x = 1.8 (rounded to the nearest tenth)

Hope this helps!! :)
If there's anything else that I can help you with, please let me know!

7 0

3 years ago

2.25x=27 Addition Property Substraction Property