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lora16 [44]
3 years ago
5

While riding on a carousel, Angela travels a distance of 65 meters every 15 seconds. What is her speed in kilometers per hour? A

. 3.9 km/hr B. 14.4 km/hr C. 15.6 km/hr D. 156.0 km/hr
Mathematics
1 answer:
Romashka-Z-Leto [24]3 years ago
5 0
C - 15.6

65 meters = 0.065
0.065 x 4 = 0.26 (in 1 minute)
0.26 x 60 = 15.6 (in a hour)
15.6km per hour
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Dr Adams is a botanist.she measures the daily height of a particular of sunflower is 60 days old.at 60 days,the height of the su
dexar [7]
Lets write a linear equation to represent this flower growth, lets call y the height of the flower in centimeters and x the number of days passed:
y = 205 + 2x
that means that the flower height y, will grow 2 centimeterrs each x days.
So if we have 235 cm height, we can find the amount of days needed if we replace in the equation and solve for x:
<span>y = 205 + 2x
</span>235 = 205 + 2x
2x = 235 - 205
2x = 30
x = 15
therefore the flower needs 15 days to reach 235 cm height
5 0
3 years ago
Use a graphing tool to solve the system. {13x+6y=−30x−2y=−4 Which ordered pair is the best estimate for the solution to the syst
Gnoma [55]
13x+6y = -30................y = -5 -13x/6
x−2y=−4...................... y = x/2 +2 <span>

If we graph both lines we can get the solution of the system (point of intersection)

The best estimate is (x,y) = (-2.625, 0.688)</span>

8 0
3 years ago
Read 2 more answers
Wright et al. [A-2] used the 1999-2000 National Health and Nutrition Examination Survey(NHANES) to estimate dietary intake of 10
xxMikexx [17]

Complete question :

Wright et al. [A-2] used the 1999-2000 National Health and Nutrition Examination Survey NHANES) to estimate dietary intake of 10 key nutrients. One of those nutrients was calcium in all adults 60 years or older a mean daily calcium intake of 721 mg with a standard deviation of 454. Usin these values for the mean and standard deviation for the U.S. population, find the probability that a randonm sample of size 50 will have a mean: (mg). They found a) Greater than 800 mg b) Less than 700 mg. c) Between 700 and 850 mg.

Answer:

0.10935

0.3718

0.9778

0.606

Step-by-step explanation:

μ = 721 ; σ = 454 ; n = 50

P(x > 800)

Zscore = (x - μ) / σ/sqrt(n)

P(x > 800) = (800 - 721) ÷ 454/sqrt(50)

P(x > 800) = 79 / 64.205295

P(x > 800) = 1.23

P(Z > 1.23) = 0.10935

2.)

Less than 700

P(x < 700) = (700 - 721) ÷ 454/sqrt(50)

P(x < 700) = - 21/ 64.205295

P(x < 700) = - 0.327

P(Z < - 0.327) = 0.3718

Between 700 and 850

P(x < 850) = (850 - 721) ÷ 454/sqrt(50)

P(x < 850) = 129/ 64.205295

P(x < 700) = 2.01

P(Z < 2.01) = 0.9778

P(x < 850) - P(x < 700) =

P(Z < 2.01) - P(Z < - 0.327)

0.9778 - 0.3718

= 0.606

3 0
3 years ago
Write the equation of the line that passes through (-1, 3) and is parallel to the line y = -x + 1.
ra1l [238]

Answer:

Step-by-step explanation:

y = -x + 1......same as y = -1x + 1.....in y = mx + b form, ur slope is in the m position....so the slope of this line is -1.

a parallel line will have the same slope.

(-1,3)...x = -1 and y = 3

slope(m) = -1

y = mx + b.....we have x,y, and m....now we need to find y int (b)

3 = -1(-1) + b

3 = 1 + b

3 - 1 = b

2 = b

so ur parallel equation is : y = -1x + 2...or just y = -x + 2

7 0
3 years ago
Find k so that the following function is continuous:<br> f(x)={kx8x2if0≤x&lt;5if5≤x.
tankabanditka [31]

Check the one-sided limits:

\displaystyle \lim_{x\to5^-}f(x) = \lim_{x\to5}kx = 5k

\displaystyle \lim_{x\to5^+}f(x) = \lim_{x\to5}8x^2 = 200

If <em>f(x)</em> is to be continuous at <em>x</em> = 5, then these two limits should have the same value, which means

5<em>k</em> = 200

<em>k</em> = 200/5

<em>k</em> = 40

3 0
3 years ago
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