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3 years ago

Find the x and y intercepts

Mathematics

1 answer:

Eduardwww [97]3 years ago

4 0

Answer:

Below

Step-by-step explanation:

The x-intercepts are the points on the graph where the lines cross the x-axis. This means that whatever the x-intercepts points are, the y's will be 0 :

(-3,0) and (3,0)

The y-intercept is the point on the graph where the line crosses the y-axis. This means that whatever the y-intercept point is, the x's will be 0 :

(0,-3)

Hope this helps!

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The surface area of a cone is given by the formula S= il + gn2. Solve the formula for l.

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Answer:

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Step-by-step explanation:

S= il + gn²
il=S-gn²
l=(S-gn²/)i

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Find all possible values of α+

const2013 [10]

Answer:

$\rm\displaystyle 0,\pm\pi$

Step-by-step explanation:

please note that to find but α+β+γ in other words the sum of α,β and γ not α,β and γ individually so it's not an equation

===========================

we want to find all possible values of α+β+γ when tanα+tanβ+tanγ = tanαtanβtanγ to do so we can use algebra and trigonometric skills first

cancel tanγ from both sides which yields:

$\rm\displaystyle \tan( \alpha ) + \tan( \beta ) = \tan( \alpha ) \tan( \beta ) \tan( \gamma ) - \tan( \gamma )$

factor out tanγ:

$\rm\displaystyle \tan( \alpha ) + \tan( \beta ) = \tan( \gamma ) (\tan( \alpha ) \tan( \beta ) - 1)$

divide both sides by tanαtanβ-1 and that yields:

$\rm\displaystyle \tan( \gamma ) = \frac{ \tan( \alpha ) + \tan( \beta ) }{ \tan( \alpha ) \tan( \beta ) - 1}$

multiply both numerator and denominator by-1 which yields:

$\rm\displaystyle \tan( \gamma ) = - \bigg(\frac{ \tan( \alpha ) + \tan( \beta ) }{ 1 - \tan( \alpha ) \tan( \beta ) } \bigg)$

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$\rm\displaystyle \tan( \gamma ) = - \tan( \alpha + \beta )$

let α+β be t and transform:

$\rm\displaystyle \tan( \gamma ) = - \tan( t)$

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$\rm\displaystyle \tan( \gamma ) = -\tan( \alpha +\beta\pm k\pi )$

therefore when k is 1 we obtain:

$\rm\displaystyle \tan( \gamma ) = -\tan( \alpha +\beta\pm \pi )$

remember Opposite Angle identity of tan function i.e -tan(x)=tan(-x) thus

$\rm\displaystyle \tan( \gamma ) = \tan( -\alpha -\beta\pm \pi )$

recall that if we have common trigonometric function in both sides then the angle must equal which yields:

$\rm\displaystyle \gamma = - \alpha - \beta \pm \pi$

isolate -α-β to left hand side and change its sign:

$\rm\displaystyle \alpha + \beta + \gamma = \boxed{ \pm \pi }$

when is 0:

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$\rm\displaystyle \tan( \gamma ) = \tan( -\alpha -\beta\pm 0 )$

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isolate -α-β to left hand side and change its sign:

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Answer:

The first step is to slove the numbers in the brackets

Step-by-step explanation:

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PEMDAS

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2 years ago