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4 years ago

What is 10.6 as a fraction

1 answer:

3 0

10.6 = 10.6 / 1

Numerator = 10.6 × 10 = 106
Denominator = 1 × 10 = 10

Numerator / Denominator = 106 / 10

The simplified fraction:

= 106/10

= 53/5

= 10 3/5

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You are to give an injection of a drug. The dosage is 0.4 mg per kilogram of bod The concentration of the drug in vial is listed

shusha [124]

Answer:

We inject 60.9628 milliliters of dosage.

Step-by-step explanation:

Given : You are to give an injection of a drug. The dosage is 0.4 mg per kilogram of bod The concentration of the drug in vial is listed as 500 ug/ml. The patient's chart Hosts weight as 168 pounds.

To find : How many milliliters (= cc) are you to inject?

Solution :

We know that,

1 pound = 0.453592 kg,

Patient's weight = 168 pounds

Patient's weight in kg = $168\times 0.453592=76.203456$ kg

The dosage is 0.4 mg per kilogram of bod.

So, dosage of patient weight = $0.4 \times 76.2035\ mg = 30.4814\ mg$

We know, 1 micro gram = 0.001 mg

Concentration of drug is given by,

$500\ \text{micro grams/ml}= 500\times 0.001\ \text{mg/ml} = 0.5\ \text{mg/ml}$

Now we are supposed to find milliliters inject,

So, milliliters of dosage required to inject is

$d= \frac{30.4814}{0.5} = 60.9628$

Therefore, We inject 60.9628 milliliters of dosage.

3 0

4 years ago

2. You draw two marbles without replacement from a bag containing

Dennis_Churaev [7]

Answer:

Please finish question.

Step-by-step explanation:

Hello! I would be able to answer your question if you finish your question.

3 0

2 years ago

Please help i dont get this at all

Tom [10]

Answer:

$\frac{20y^{2} a^{2} }{41bx^{3} }$

Step-by-step explanation:

1) Flip the second fraction and change the operation to multiplication:

$\frac{5x^{2}y^{3} }{2a^{5}b^{4} } * \frac{8a^{7}b^{3} }{41x^{5}y }$

2) Cross cancel factors:

$\frac{5y^{2} }{2b } * \frac{8a^{2} }{41x^{3} }$

3) Multiply:

$\frac{40y^{2} a^{2} }{82bx^{3} }$

4) Simplify:

$\frac{20y^{2} a^{2} }{41bx^{3} }$

4 0

3 years ago

Read 2 more answers

on the design of the new car the steering wheel has a diameter with endpoints at (4 9) and (12,3) what are the center and raduis

xeze [42]

Answer:

The center of the circle is point (8 , 6)

Step-by-step explanation:

* At first lets revise how to find the mid-point between two points

- If (x1 , y1) and (x2 , y2) are the end point of a segment

- If (x , y) is the mid-point of this segment

- To find x add x1 and x2, then divide the answer by 2

∴ x = (x1 + x2)/2

- Similar to find y add y1 and y2, then divide the answer by 2

∴ y = (y1 + y2)/2

∴ The mid-point (x , y) = [(x1 + x2)/2 , (y1 + y2)/2]

* Now lets solve the problem

- The center of the circle is the mid-point of the diameter

- Consider the center of the circle is (x , y)

- (x , y) is the mid-point of the diameter of the circle with endpoints

(4 , 9) and (12 , 3)

- Let (4 , 9) is (x1 , y1) and (12 , 3) is (x2 , y2)

∵ x1 = 4

∵ x2 = 12

∵ x = (x1 + x2)/2

∴ x = (4 + 12)/2 = 16/2 = 8

* Similar

∵ y1 = 9

∵ y2 = 3

∵ y = (y1 + y2)/2

∴ y = (9 + 3)/2 = 12/2 = 6

∴ (x , y) = (8 , 6)

* The center of the circle is point (8 , 6)

6 0

4 years ago

Read 2 more answers

In the figure, the horizontal lines are parallel and AB=BC=CD. If LM = 8, find JM.

hram777 [196]

⇒ If AB = BC = CD then ML = LK = KJ

Now, JM = LM + KL + KJ

⇒ JM = LM + LM + LM

⇒ JM = 3 × LM

⇒ JM = 3 × 8

⇒ JM = 24 units

5 0

3 years ago