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Sholpan [36]
3 years ago
12

The College Board conducted research studies to estimate the mean SAT score in 2016 and its standard deviation. The estimated me

an was 1020 points out of 1600 possible points, and the estimated standard deviation was 192 points. Assume SAT scores follow a normal distribution. Using the Empirical Rule, about 95% of the scores lie between which two values?
a. 768 to 1358
b. 636 to 1404
c. 620 to 1520
d. 828 to 1212
e. 724 to 1486
Mathematics
1 answer:
Svetach [21]3 years ago
6 0

Answer:

sorry i dont know

Step-by-step explanation:

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3 years ago
Find the circumference and area of the circle. Round to the nearest tenth.<br> 2 m
Fed [463]
  • Radius=2m

Circumference:-

\\ \bull\sf\dashrightarrow 2\pi r

\\ \bull\sf\dashrightarrow 4(3.14)

\\ \bull\sf\dashrightarrow 12.56m

Area.

\\ \bull\sf\dashrightarrow \pi r^2

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8 0
2 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%20%5Crm%20%5Cint_%7B0%7D%5E2%20%5Cleft%28%20%5Csqrt%5B3%5D%7B%20%7Bx%7D%5E%7B2%7D%20%20%2B%20
Verizon [17]

If f(x) has an inverse on [a, b], then integrating by parts (take u = f(x) and dv = dx), we can show

\displaystyle \int_a^b f(x) \, dx = b f(b) - a f(a) - \int_{f(a)}^{f(b)} f^{-1}(x) \, dx

Let f(x) = \sqrt{1 + x^3}. Compute the inverse:

f\left(f^{-1}(x)\right) = \sqrt{1 + f^{-1}(x)^3} = x \implies f^{-1}(x) = \sqrt[3]{x^2-1}

and we immediately notice that f^{-1}(x+1)=\sqrt[3]{x^2+2x}.

So, we can write the given integral as

\displaystyle \int_0^2 f^{-1}(x+1) + f(x) \, dx

Splitting up terms and replacing x \to x-1 in the first integral, we get

\displaystyle \int_1^3 f^{-1}(x) \, dx + \int_0^2 f(x) \, dx = 2 f(2) - 0 f(0) = 2\times3+0\times1=\boxed{6}

7 0
2 years ago
-6x+6y=6<br> -6x+3y=-12<br> How do you solve this problem?
sergij07 [2.7K]

Answer:

That's called system of equations. it is like adding and subtracting.

Step-by-step explanation:

first you want to find x or y. i will choose x. in order to do that you need to put one, ill do the first one but you can do first or second, and change it to negative (-6x+6y=6) or -(-6x+6y=6), changing it to 6x - 6y = -6. then the two x's will be cancled since 6-6 is 0. now you add 6y and 3y, and 6 with -12. get your answer, and do the same thing to y, too. sorry if its a bit confusing, took me a while to learn it too. this is highschool stuff so thats why you will although im im middle too!

3 0
3 years ago
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