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Semmy [17]
3 years ago
7

J(h - 9) + 2; use h=9, and j = 8

Mathematics
1 answer:
shepuryov [24]3 years ago
3 0

It should be -6

8(8-9)+2

Step-by-step explanation:

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I need help pls help me what is the answer to -2(8)
AnnZ [28]

Answer:

-16

Step-by-step explanation:

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3 years ago
Factor the following equation to find its zeros. y = x² - 36
alukav5142 [94]

Answer:

x = 6, x = - 6

Step-by-step explanation:

Given

y = x² - 36

To find the zeros let y = 0, that is

x² - 36 = 0 ← x² - 36 is a difference of squares and factors in general as

a² - b² = (a - b)(a + b), thus

x² - 36 = 0

x² - 6² = 0

(x - 6)(x + 6) = 0 ← in factored form

Equate each factor to zero and solve for x

x - 6 = 0 ⇒ x = 6

x + 6 = 0 ⇒ x = - 6

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3 years ago
Find the area of the regular polygon​
gregori [183]

Answer:To find the area of a regular polygon, all you have to do is follow this simple formula: area = 1/2 x perimeter x apothem. Here is what it means: Perimeter = the sum of the lengths of all the sides. Apothem = a segment that joins the polygon's center to the midpoint of any side that is perpendicular to that side.

Step-by-step explanation:

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8 0
3 years ago
Mr. Whittaker’s science class uses tide gauges to measure annual variations in water levels at different parts of a river, and t
strojnjashka [21]

Answer:

-1.05 mm/year

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Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Check that 2b+b and 3b have the same value when b is 1,2, and 3. Do 2b+b and 3b have the same value for all values of b? Explain
Inessa [10]

Answer:

Expression 2b+b and 3b have same values for all values of b.

Step-by-step explanation:

Given the two expression 2b+b and 3b and values of b as 1, 2 and 3.

Consider first expression that is, 2b+b.

Substituting the value of b=1,

2\left(1\right)+\left(1\right)=2+1=3 ....1

Substituting the value of b=2,

2\left(2\right)+\left(2\right)=4+2=6 ....2

Substituting the value of b=3,

2\left(3\right)+\left(3\right)=6+3=9 ....3

Consider second expression that is, 3b.

Substituting the value of b=1,

3\left(1\right)=3 ....4

Substituting the value of b=2,

3\left(2\right)=6 ....5

Substituting the value of b=3,

3\left(3\right)=9 ....6

For value of b=1, equation 1 and equation 4 are same, for value of b=2, equation 2 and equation 5 are same and for value of b=3 equation 3 and equation 6 are same.

Therefore both expression are same for all values of b.

3 0
3 years ago
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