Answer:
Step-by-step explanation:
This isn’t a dating app sorry hun
The answer is 8.
half of 16 is 8
The value of x in the given diagram is 10
<h3>Similar triangles </h3>
From the question, we are to determine the value of the side labeled x
First, we will find the value of side |BC|
By the <em>Pythagorean theorem</em>, we can write that
|BC|² = 12² + 16²
|BC|² = 144 + 256
|BC|² = 400
|BC| = √400
|BC| = 20
Now,
Since ΔABC and ΔDEF are similar, we can write that
|BC| / |EF| = P ΔABC / P ΔDEF
But,
P ΔABC = 12 + 16 + 20 = 48
Thus,
|BC| / |EF| = P ΔABC / P ΔDEF becomes
20/ |EF| = 48/24
20/x = 2
x = 20/2
x = 10
Hence, the value of x in the given diagram is 10
Learn more on Similar triangles here: brainly.com/question/24085502
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(PLEASE GIVE THIS BRAINLIEST)Multiply the numbers
3
8
=
6
−
1
⋅
7
2
+
1
4
3
8
=
6
w
−
1
⋅
7
2
w
+
14
83=6w−1⋅27w+14
3
8
=
6
−
7
2
+
1
4
Combine multiplied terms into a single fraction
3
8
=
6
−
7
2
+
1
4
3
8
=
6
w
−
7
2
w
+
14
83=6w−27w+14
3
8
=
6
+
−
7
2
+
1
4
3
8
=
6
w
+
−
7
w
2
+
14
83=6w+2−7w+14
3
Find common denominator
3
8
=
6
+
−
7
2
+
1
4
3
8
=
6
w
+
−
7
w
2
+
14
83=6w+2−7w+14
3
8
=
2
⋅
6
2
+
−
7
2
+
2
⋅
1
4
2
3
8
=
2
⋅
6
w
2
+
−
7
w
2
+
2
⋅
14
2
83=22⋅6w+2−7w+22⋅14
4
Combine fractions with common denominator
3
8
=
2
⋅
6
2
+
−
7
2
+
2
⋅
1
4
2
3
8
=
2
⋅
6
w
2
+
−
7
w
2
+
2
⋅
14
2
83=22⋅6w+2−7w+22⋅14
3
8
=
2
⋅
6
−
7
+
2
⋅
1
4
2
3
8
=
2
⋅
6
w
−
7
w
+
2
⋅
14
2
83=22⋅6w−7w+2⋅14
5
Multiply the numbers
3
8
=
2
⋅
6
−
7
+
2
⋅
1
4
2
3
8
=
2
⋅
6
w
−
7
w
+
2
⋅
14
2
83=22⋅6w−7w+2⋅14
3
8
=
1
2
−
7
+
2
⋅
1
4
2
3
8
=
12
w
−
7
w
+
2
⋅
14
2
83=212w−7w+2⋅14
6
Multiply the numbers
3
8
=
1
2
−
7
+
2
⋅
1
4
2
3
8
=
12
w
−
7
w
+
2
⋅
14
2
83=212w−7w+2⋅14
3
8
=
1
2
−
7
+
2
8
2
3
8
=
12
w
−
7
w
+
28
2
83=212w−7w+28
7
Combine like terms
3
8
=
1
2
−
7
+
2
8
2
3
8
=
12
w
−
7
w
+
28
2
83=212w−7w+28
3
8
=
5
+
2
8
2
3
8
=
5
w
+
28
2
83=25w+28
8
Multiply all terms by the same value to eliminate fraction denominators
3
8
=
5
+
2
8
2
3
8
=
5
w
+
28
2
83=25w+28
2
⋅
3
8
=
2
(
5
+
2
8
2
)
2
⋅
3
8
=
2
(
5
w
+
28
2
)
2⋅83=2(25w+28)
9
Cancel multiplied terms that are in the denominator
2
⋅
3
8
=
2
(
5
+
2
8
2
)
2
⋅
3
8
=
2
(
5
w
+
28
2
)
2⋅83=2(25w+28)
2
⋅
3
8
=
5
+
2
8
2
⋅
3
8
=
5
w
+
28
2⋅83=5w+28
10
Multiply the numbers
2
⋅
3
8
=
5
+
2
8
2
⋅
3
8
=
5
w
+
28
2⋅83=5w+28
3
4
=
5
+
2
8
3
4
=
5
w
+
28
43=5w+28
11
Subtract
2
8
28
28
from both sides of the equation
3
4
=
5
+
2
8
3
4
=
5
w
+
28
43=5w+28
3
4
−
2
8
=
5
+
2
8
−
2
8
3
4
−
28
=
5
w
+
28
−
28
43−28=5w+28−28
12
Simplify
Subtract the numbers
Subtract the numbers
−
1
0
9
4
=
5
−
109
4
=
5
w
−4109=5w
13
Divide both sides of the equation by the same term
−
1
0
9
4
=
5
−
109
4
=
5
w
−4109=5w
−
1
0
9
4
5
=
5
5
−
109
4
5
=
5
w
5
5−4109=55w
14
Simplify
Divide the numbers
Cancel terms that are in both the numerator and denominator
Move the variable to the left
=
−
1
0
9
2
0
w
=
−
109
20
w=−20109
