Question

Assistance again, please?

Answer 1

You're going to need about an 8 feet tall 19 feet wide wrapping paper.

Answer 2

We're finding how much surface he needs in order to entirely wrap the box, so let's use the surface area form to find it.

$SA: A_1 + A_2 + A_3$

$A_1 = 2(5 \cdot 3)$ (front and back)
$A_2 = 2(3 \cdot 14)$ (two sides)
$A_3 = 2(5 \cdot 14)$ (top and bottom)

Hence, our SA becomes $2(5 \cdot 3) + 2(3 \cdot 14) + 2(5 \cdot 14)$
$= 254 ft^{2}$ of wrapping paper.