Step-by-step explanation:
For the quadratic equation to have 1 repeated real solution, the discriminant b² - 4ac must be zero.
=> (-z)² - 4(z - 5)(5) = 0
=> z² - 20(z - 5) = 0
=> z² - 20z + 100 = 0
=> (z - 10)² = 0
Therefore z = 10.
the answer is 3 I bet the oven is hot tbh
Answer:
Answer: the answer is right, try putting a $ in front of it, sometimes those programs mess up if you aren't specific
1
-2 + (-4) = -6 + 7 = 1
evaluate = solve
