We are given the area of the region under the curve of the function f(x) = 5x + 7 with an interval [1, b] which is 88 square units where b > 1
We need to find the integral of the function f(x) = 5x + 7 with the limits 1 and b
5/2 x^2 + 7x (limits: 1, b)
substitute the limits:
5/2 (1^2) + 7 (1) - 5/2 b^2 + 7b = 0
solve for b
Then after solving for b, this would be your interval input with 1: [1, b].<span />
Answer:
Step-by-step explanation:
https://www.toppr.com/ask/question/find-the-value-of-k-such-that-the-polynomial-x2k6x22k1/
<span>(1/3) * 4 = 4/3 = 1 and 1/3 miles</span>
Answer:
First option y=3/5x
Step-by-step explanation:
Because if you look on the graph, at x=5, y=3
in the equation, plug in x=5, you cancel out denominator left with y=3
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