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Scorpion4ik [409]
3 years ago
8

5.. A hemisphere has a radius of 9 centimeters. Find the volume of the hemisphere in cubic centimeters. Round to the

Mathematics
1 answer:
Naya [18.7K]3 years ago
5 0
The correct answer is 900
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Does anyone know the answers to these questions
notsponge [240]

Which questions. There is no pic

8 0
3 years ago
Solve x2 + 14x = −24 by completing the square.
Aleks04 [339]

Option A

The solution set of the equation is {-12, -2}

<h3><u>Solution:</u></h3>

Given equation is:

x^2 + 14x = -24

We have to find the solution set of this equation by completing the square

First, rearrange the equation so that only zero will be on the right side:

x^2 + 14x + 24 = 0 ----- eqn 1

<em><u>The general form of quadratic equation is:</u></em>

ax^2 + bx + c = 0 where a \neq 0

On comparing the given eqn 1 with general quadratic equation, we get

a = 1

b = 14

c = 24

In completing the square, we take half of coefficient of middle term "x" and then square it. Then we add it on both sides of the equation

So to complete the square, add (\frac{b}{2})^2 to both sides of the equation

x^2 + 14x + 24 + (\frac{14}{2})^2 = (\frac{14}{2})^2

x^2 + 14x + 24 + 7^2 = 7^2\\\\x^2 + 14x + 24 + 49 = 49

x^2 + 14x + 24 + 49 = 49\\\\x^2 + 14x + 49 = 49 - 24\\\\x^2 + 14x + 49 = 25\\\\(x + 7)(x + 7) = 25\\\\(x + 7)^2 = 25

Take square root on both sides

x + 7 = \sqrt{25}

x+7=\pm 5

Now make two equations

x + 7 = + 5 and x + 7 = -5

x = +5 - 7 = -2

x = -2

And,

x + 7 = -5

x = -5 - 7 = -12

x = -12

Therefore, the solution set of the equation is {-12, -2} and option A is correct

6 0
3 years ago
Read 2 more answers
Sven has a lawn mowing business. He earns $30 for every 2 weeks of mowing
NeX [460]
Whats your question? What are you trying to find?
4 0
2 years ago
Identify the volume of a cone with base area 64π m2 and a height 4 m less than 3 times the radius, rounded to the nearest tenth.
melomori [17]
V=basearea times 1/3 times height
basearea=6<span>4π m2
hmm, they try to make it difficult

basearea=circle=pir^2
pir^2=64pi
divide by pi
r^2=64
sqrt
r=9

h is 4 les than 3 time r
h=-4+3(8)
h=-4+24
h=20

v=1/3*64pi*20=1280pi/3 m^3=1350.4

C
</span>
4 0
4 years ago
Find one value of x that is a solution to the equation (x^2+3)^2=4x^2+12
Westkost [7]

Answer:

{( {x}^{2} + 3) }^{2}  =  {4x}^{2}  + 12

\bf \purple{ {(x + y)}^{2} =  {x}^{2} + 2xy +  {y}^{2}  }

{( {x}^{2}) }^{2}  + 2({x)}^{2} (3) +  {(3)}^{2}  =  {4x}^{2}  + 12

{x}^{4}  +  {6x}^{2}  + 9 =  {4x}^{2}  + 12

{x}^{4}  =  {4x}^{2}  -  {6x}^{2} + 12 - 9

{x}^{4}  =   { - 2x}^{2}  + 3

( {x}^{2}  \times  {x}^{2}) =  { - 2x}^{2}  + 3

2 \times  {x}^{2} =  { - 2x}^{2}  + 3

=  \frac{ { - 2x}^{2} + 3 }{ {2x}^{2} }

= 3

4 0
3 years ago
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