Answer:
The toy's maximum height is .
Step-by-step explanation:
The equation that models the toy's height in feet from the ground at t seconds after he threw it is given by :
.....(1)
It is required to find the toy's maximum height. For maxima or minima, put
Plugging the value of t in above equation,
Now put t = 1.75 s in equation (1) such that,
So, the toy's maximum height is .
Answer:
Height of the pole = 9.17 chi.
Length of the rope = 12.17 chi.
Step-by-step explanation:
Given that the rope is hanging from the top of a pole having height x chi and the portion of the rope lying on the ground is 3 chi.
So, the length of the rope= x + 3 chi.
Let AB represents the pole in the figure, and one end of the rope is at point A.
When the rope is tightly stretched, let C be the other end of the rope as shown in the triangle.
The length of the rope = AC.
\Rightarrow AC=x+3 chi.
Distance from the bottom of the pole, point A, to the other end of the pole, point B, is 8 chi.
So, BC=8 chi.
As the triangle ABC is a right-angled triangle, so by using Pythagoras theorem,
chi.
Hence, the height of the pole, chi,
and the length of the rope, chi.