Answer:
Following is the program in C language :
#include <stdio.h> // header file
#define n 5 // macro
int main() main function
{
int a[n],k1; // variable and array declaration
printf("Enter the element:\n");
for(k1=0;k1<n;++k1) //iterating the loop
{
scanf("%d",&a[k1]);//Read the values by user
}
printf("Output in Reverse Order:\n");
for(k1=n-1;k1>=0;--k1)//iterating the loop
{
printf(" %d ",a[k1]); //Display the values
}
return 0;
}
Output:
Enter the element:
4
3
45
67
89
Output in Reverse Order: 89 67 45 3 4
Explanation:
Following is the description of the program
- Define a macro "n" with value 5 after the header file.
- Declared an array "a" and defined the size of that array by macro i.e "n".
- Read the value by the user by using scanf statement in the array "a"
- Finally In the last for loop display the values of array "a" by space.
The answer is entrepreneurial and bureaucratic. Organizations
that are large and small can achieve higher sales and other profit by properly
matching their needs with the structure they use to operate. the structure of an organization can help or
hinder its progress toward accomplishing these goals and This are specific set
up of organizations and ways to accomplish different goals.
That is a true statement. Hope this was helpful!
Answer:
The answer is letter B.
Explanation:
The option that will most effectively
reduce her or his radiation exposure to that source is Standing 8 ft from the source for 2 minutes.
Answer:
//Code is created using java
import java.util.*;
// returns the sum
public int sum(int N)
{
if(N==1)
return (1);
else
return N+sum(N-1);
}
// code to return the Bipower ouput
public int BiPower(int N)
{
if(N==1)
return (2);
else
return 2*BiPower(N-1);
}
// Code to return TimesFive output
public int TimesFive(int N)
{
if(N==1)
return 5;
else
return 5 + timesFive(N-1);
}
public static void main(String args[])
{
//Prompts the user to enter a nonnegative integer
int N = Integer.parseInt.(console.readLine("Enter a nonnegative integer: "));
//Outputs the sum, Bipower and TimesFive
System.out.println(sum(n));
System.out.println(BiPower(n));
System.out.println(TimesFive(n));
}
}
