Decimals are based on the preceding powers of 10. Thus, as we move from left to right, the place value of digits gets divided by 10, meaning the decimal place value determines the tenths, hundredths and thousandths. A tenth means one tenth or 1/10. In decimal form, it is 0.1.
Hi, you haven't provided the programing language in which you need the code, I'll just explain how to do it using Python, and you can apply a similar method for any programming language.
Answer:
def rightMost(num):
lenNum = len(str(num))
rightNum = num%(10**(lenNum-1))
print(rightNum)
return(rightNum)
Explanation:
In this function we receive an integer number, then we find how many digits this number has, and finally, we find the rightmost digits; the main operation is modulo (takes the remainder after a division), what we want is to take all the digits except the first one, for that reason we find the modulo of the number when divided by ten to the power of the length of the number minus one, for example, if the number is 2734 we divided by 10^(4-1), where four is the length of the number, this way we get 2734/1000 and the module of it is 734.
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i dont have the time to read it right now, but i was able to find you this link that should hopefully help- you out!
Answer:
Q=It
and
p=IV
Given, v=9V P= 7W
I=P/V
I =7/9
Also, time(t) from 9am to 12pm is 3hrs
Converting into sec =3×3600
t=10800
Q= 7/9 ×10800
Q =8400C
Answer:
zero ( 0) times.
Explanation:
In the code;
i = 2
while ( i > 2){
i = floor( i/2 );
z = z + 1;
}
the variable " i " is assigned the integer " 2 ", then the while statement loops with a condition of a greater " i " value and divides the value by two for every loop.
But in this case, the while statement is not executed as the value of " i " which is 2 is not greater than but equal to two.
