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mixer [17]
2 years ago
7

Which linear equation has a slope of 3 and a y-intercept of –2?

Mathematics
2 answers:
nordsb [41]2 years ago
4 0
The\ slope-intercept\ form:y=mx+b\\\\m-the\ slope\\b-y-intercept\\\\m=3;\ b=-2\\\\therefore\\\\\boxed{y=3x-2}
iVinArrow [24]2 years ago
3 0

Answer:

B

Step-by-step explanation:

understand the order first the apply the variables in the formula Y=mx+b.

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Select the correct comparison
seropon [69]

Answer:

pretty sure its d

Step-by-step explanation:

Because a has spread out dots and b has them all towered and neat so d

5 0
3 years ago
can someone help me understand this, please? For some reason my answer is correct but I need to understand how did I found the c
Morgarella [4.7K]

Answer with step-by-step explanation:

The way the question is worded, this actually shouldn't be correct. The correct answer should be 3:4.

Because the trapezoids are similar, we can find the ratio of their perimeters by actually just finding the ratio of their sides.

Why?

By definition, the corresponding sides of a polygon are in a constant proportion. The perimeter is simply the sum of all sides of the polygon. Since we're just adding the sides, the proportion will still be maintained.

Therefore, we'll just need to ratio of their corresponding sides. The only two corresponding sides that are marked are \overline{RS} and \overline{AB}.

The ratio of \overline{RS}:\overline{AB} is 18:24\implies \boxed{3:4}.

The reason why it ideally should be 3:4 and not 4:3 is because the question states RTSU\sim ABCD, which mentions RSTU first, so our answer should follow this respective order. I believe you were marked right anyways because the specific order is not specified, but generally, you want to give your answer respectively by default.

3 0
2 years ago
The area of a mirror is 225 Square inches, it's width is
Zepler [3.9K]

NO. The mirror will not fit in a space that is 15 inches by 16 inches

<em><u>Solution:</u></em>

Given that area of mirror is 225 square inches

width = 13\frac{3}{4} \text{ inches }

Converting the above mixed fraction we get,

width = 13\frac{3}{4} = \frac{13 \times 4 + 3}{4} = \frac{55}{4} \text{ inches }

Let us find the length of mirror

The area of mirror is given as:

area of mirror = length x width

Substituting the given values,

225 = length \times \frac{55}{4}\\\\length = 225 \times \frac{4}{55}\\\\length = 225 \times 0.0727\\\\length = 16.36

Thus length of mirror is 16.36 inches

<em><u>Will the mirror fit in a space that is 15 inches by 16 inches?</u></em>

NO. The mirror will not fit in a space that is 15 inches by 16 inches

Because length of mirror is 16.36 inches whereas the given space is 15 inches long

16.36 > 15 so the length of mirror will not fit inside the space

Also width of mirror is \frac{55}{4} = 13.75 inches which is less than the given space whose width is 16 inches

13.75 < 16 so the width of mirror will not fit inside the space

7 0
3 years ago
3/2-x + 5/4-2x - 1/x-2 =4
dimaraw [331]
Is there like a question???
3 0
3 years ago
Can anyone show me the steps in order solve this problem
STatiana [176]
M∠A = 42°   [isosceles triangle]

m∠B = 180 - 42 - 42 = 96°  [in a triangle, the three interior angles always add to 180°]

m∠C = 180 - 96 - (x+12)
m∠C = 84 - x - 12
m∠C = 72 - x

2x+9 + 3x-1 + 72-x = 180
4x + 80 = 180
4x = 180 - 80
4x = 100
x = 100/4
x = 25

m∠C = 72 - x = 72 - 25 = 47°

<span>I hope this helped</span>

8 0
3 years ago
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