Which test point holds true for the inequality 3/2y-2x>=1? Where does the shaded area lie for this inequality? The test point
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I would say the answer would be 29.17% because =29.17%
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Supposse that the distance from the point to the point
is equal to the distance from
to the point
. Then, by the formula of the distnace we must have
cancel the square root and the 's, and then expand the parenthesis to obtain
then, simplifying we obtain
therfore we must have
this means that the points satisfying the propertie must have first component equal to 5. So we can give a lot of examples of such points: . The set of this points give us a straight line and the points (3,0) and (7,0) are symmetric with respect to this line.