Question

A football is kicked vertically upward from a height of 3 feet with an initial speed of 70 feet per second. The formula h=3+70t-16t^2 describes the​ ball's height above the​ ground, h, in​ feet, t seconds after it was kicked. Use this formula to find the​ ball's height 3 seconds after it was kicked.
Q. The​ ball's height, 3 seconds after it was​ kicked, was
???? feet.

Answer 1

Answer:

69 feet

Step-by-step explanation:

3 seconds is a unit of time, t.  So if we want the height of the ball, h, 3 seconds after it was kicked, we plug in 3 for t and solve for h:

$h=3+70(3)-16(3)^2$ which simplifies to

h = 3 + 210 - 144 so

h = 69 feet