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meriva
3 years ago
7

Two equally charged spheres of mass 1.00 g are placed 2.00 cm apart. When released, the initial acceleration of each sphere is 2

56 m/s2 . What is the magnitude of the charge on each sphere? You may assume that the only force acting on each sphere is the electric force due to the other sphere.
Physics
1 answer:
shusha [124]3 years ago
5 0

Answer:

q = 0.107 \mu C

Explanation:

As we know that net force is given by

F = ma

here we have

m = 1.00 g = 0.001 kg

also we know that acceleration is given as

a = 256 m/s^2

now force is given as

F = 0.001(256) = 0.256 N

now by the formula of force we know that

F = \frac{kq_1q_2}{r^2}

0.256 = \frac{(9\times 10^9)q^2}{(0.02)^2}

now for solving charge we have

q = 0.107 \mu C

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Answer:

charged pith ball works well to show the Coulomb force between two charged objects. If a glass rod is rubbed with silk, the silk rubs some electrons off the rod. The rod thus becomes positively charged. ... Since like charges repel, the pith balls repel one another.

Explanation:

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3 years ago
You throw a ball straight up with an initial velocity of 15.0 m/s. It passes a tree branch on the way up at a height of 7.00 m.
Gwar [14]

Answer:

0.95 seconds

Explanation:

t = Time taken

u = Initial velocity = 15 m/s

v = Final velocity

s = Displacement

a = Acceleration = 9.81 m/s² (downward positive, upward negative)

Time taken by the ball to reach the maximum height

v=u+at\\\Rightarrow t=\frac{v-u}{a}\\\Rightarrow t=\frac{0-15}{-9.81}\\\Rightarrow t=1.52\ s

Maximum height

v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{0^2-15^2}{2\times -9.81}\\\Rightarrow s=11.47\ m

Distance between maximum height of the ball and the branch is 11.47-7 = 4.46 m

So, the distance that will be covered on the way down is 4.46 m

Now

u = 0

s = 4.46

s=ut+\frac{1}{2}at^2\\\Rightarrow 4.46=0\times t+\frac{1}{2}\times 9.81\times t^2\\\Rightarrow t=\sqrt{\frac{4.46\times 2}{9.81}}\\\Rightarrow t=0.95\ s

Time taken by the ball from the maximum height to the tree branch is 0.95 seconds.

Total time taken from the moment the ball is thrown to reach the tree branch is 1.52+0.95 = 2.47 seconds

7 0
3 years ago
9. The acceleration due to gravity on the
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W=mg
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6 0
3 years ago
A 214 kg boat is sinking in the ocean. The force of gravity that draws the boat down is partially offset by the buoyant force of
bixtya [17]

Answer:

3.68 m/s^2

Explanation:

We are given that

Mass of boat=m=214 kg

F=1310 N

We have to find the acceleration of the boat.

Net force=mg-F=mg-1310

Where g=9.8 m/s^2

F_{net}=214\times 9.8-1310=787.2 N

We know that

Acceleration ,a=\frac{F_{net}}{m}

Using the formula

a=\frac{787.2}{214}=3.68 m/s^2

Hence, the acceleration of the boat=3.68 m/s^2

6 0
3 years ago
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