Answer:
Ans 171.875 m(according to the units)
Explanation:
As we know,
to find the distance, we need to use this eqn..
speed = distance/ time
So, time is 1.92 s (as given)
the speed is 330 m/s ( in air speed)
so to find it is easy to find by using this
eqn..
speed =distance/time
330 =distance/1.92
330/1.92 =distance
171.875 = distance
Answer:
D,E,F
Explanation:
d. Earth's geographic north pole is actually a magnetic south pole.
e. The south poles of two bar magnets will repel each other.
f. The north pole of a bar magnet will attract the south pole of another bar magnet.
In a magnetic field like poles repel and unlike poles attract each other. The like poles which is south to south or north to north repel each other and the unlike poles which is north to south or south to north attract each other which makes E and F correct.
A is correct because compasses points to the North Pole when places in the Southern Hemisphere.
Answer:
5.1m
Explanation:
Use the fourth key equation of accelerated motion
vf^2=vi^2+2aΔd
we know vf is = 0 because that is when the ball reaches it's peak (not going up anymore)
0=vi^2+2aΔd
and we can rearrange for Δd, which is what you need
-vi^2=2aΔd
Δd = -vi^2/2a
Now we can plug in the values
Δd = -vi^2/2a
Δd = -(10m/s)^2/2(-9.8)
Δd = -100/-18.6
Δd = 5.10m
The distance traveled by the hockey player is 0.025 m.
<h3>The principle of conservation of linear momentum;</h3>
- The principle of conservation of linear momentum states that, the total momentum of an isolated system is always conserved.
The final velocity of the hockey play is calculated by applying the principle of conservation of linear momentum;
The time taken for the puck to reach 15 m is calculated as follows;
The distance traveled by the hockey player at the calculated time is;
Learn more about conservation of linear momentum here: brainly.com/question/7538238
Answer:
Explanation:
Using the formula to calculate the maximum height
H = u²/2g
u is the initial velocity = 18m/s
g is the acceleration due to gravity = 9.81
H = 18²/2(9.81)
H = 324/19.62
H = 16.51m
The maximum height in which the ball reached from the ground = 85m + 16.51m = 101.5m
b) Time of fight = 2u/g
T = 2(18)/g
T = 36/9.81
T = 3.67s
It took the ball 3.67s later to reach the ground
3) To get the final velocity of the ball as it hits the ground, we need to calculate the horizontal component of the velocity,
Ux = Ucosθ
ux = 18cos 90 (angle of launch is 90 since the ball is thrown vertically upwards)
Ux = 18(0)
Ux = 0m/s
Hence the final velocity of the ball as it hits the ground is 0m/s