Trapezoid
it has four sides and 1 set of parallel lines
Answer:
It repeats over and over..
Step-by-step explanation:
<h3>
Answer: Choice B</h3>
Reflection along y axis
Translation:
which means we shift 3 units down
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Explanation:
Let's track point A to see how it could move to point A'.
If we were to reflect point A over the vertical y axis, then A(-4,4) would move to (4,4). The x coordinate flips in sign, but the y coordinate stays the same.
The diagram shows that A' is located at (4,1) instead of (4,4). So a y-axis reflection isn't enough to move A to A', but we can shift that reflected point three units down. That will move (4,4) to (4,1) which is exactly where we want to end up. Note how we subtract 3 from the y coordinate and x stays the same. So that explains the notation 
Overall, this points to choice B as the final answer. If we apply these steps to points B and C, you should find that they'll land on B' and C' respectively. Apply this to all of the points on the triangle ABC, and it will move everything to triangle A'B'C'.
Answer:
40 km on the highway
30 km on the city roads
Step-by-step explanation:
Let x = highway
Let y = city road
The time formula: time = distance / speed.
1) Since we do not know the distance travelled on the highway and city roads but we do know the total time taken, we can say x + y = 70. Set the distances x and y and all equated to 2 hours, since we do not know them, nor do we know the time. This is called a system of equations.
x + y = 70
x/80 + y/20 = 2
2) Solve the system of equations using substitution.
x = 70 - y
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70 - y/80 + y/20 = 2
70 + 3y/80 = 2
y = 30
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x + 30 = 70
x = 70 - 30
x = 40
Therefore, the delivery truck travelled 40 km on the highway and 30 km on the city roads.
Speed = Distance/Time
Cat's Speed 9ft/s
Dog's Speed 6ft/s
Let x be the distance travelled by the Cat,
the distance travelled by te dog =165 -x,
and t, the time spend
Cat's Speed 9ft/s =x/t
Dog's Speed 6ft/s =(165 - x)/t
Solving for t you will get t= 11 seconds