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3 years ago

What is the simplified form of the following expression 3 4x/5

Mathematics

1 answer:

Tanya [424]3 years ago

4 0

Answer:

the correct answer is

3(4x/5)

therefore we multiple

12x/5

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One can convert temperature from Fahrenheit into Newton using the formula N=11/60(F-32) . What is the temperature in Fahrenheit

Rasek [7]

We are given

$N=\frac{11}{60} (F-32)$

Since, we have to solve for F

so, we will isolate F on anyone side

step-1:

Multiply both sides by 60

$60\times N=60\times \frac{11}{60} (F-32)$

$60N=11 (F-32)$

step-2:

Divide both sides by 11

$\frac{60N}{11} =\frac{11(F-32)}{11}$

$\frac{60}{11}N =F-32$

step-3:

Add both sides by 32

$\frac{60}{11}N+32 =F-32+32$

$\frac{60}{11}N+32 =F$

so, we get

$F=\frac{60}{11}N+32$ ................Answer

5 0

3 years ago

Medal will be awarded:. When constructing an inscribed polygon with a compass and straightedge, how should you start the constru

Ymorist [56]

The draw an inscribed polygon inside the circle, the very thing to do is to draw the circle. Thus, the answer is the fourth choice, "Place a point on your paper and then use a compass to construct a circle". After which, we can locate the vertices of the polygon in the circumference of the circle and connect them to make the polygon.

6 0

3 years ago

The lateral edge PA of a triangular pyramid ABCP is perpendicular to the base and PA = 2sqrt5 in. The base edges AB = 10 in, AC

DIA [1.3K]

Answer:

PQ = √84 = 2√21 in ≈ 9.165 in

Step-by-step explanation:

The base edges AB = 10 in, AC = 17 in, and BC = 21 in

Q ∈ BC and AQ is the altitude of the base.

Let BQ = x in ⇒ CQ = (21 - x) in

ΔAQB a right triangle at Q

∴ AQ² = AB² - BQ² = 10² - x² ⇒(1)

ΔAQC a right triangle at Q

∴ AQ² = AC² - CQ² = 17² - (21-x)² ⇒(2)

Equating (1) and (2)

∴ 10² - x² = 17² - (21-x)²

∴ 10² - x² = 17² - (21² - 42x + x²)

∴ 10² - x² = 17² - 21² + 42x - x²

∴ 10² - 17² + 21² = 42x

∴ 42x = 252

∴ x = 252/42 = 6

Substitute at (1)

∴ AQ² = AB² - BQ² = 10² - x² = 100 - 36 = 64 = 8²

∴ AQ = 8 in

∵ The lateral edge PA of a triangular pyramid ABCP is perpendicular to the base

∴ PA⊥AQ

∴ ΔPAQ is a right triangle at A,

PA = 2sqrt5 in and AQ = 8 in

∴ PQ (hypotenuse) = √(PA² + AQ²)

∴ PQ = √[(2√5)² + 8²] = √(20+64) = √84 = 2√21 in ≈ 9.165 in

6 0

2 years ago

Which expression is equivalent to *picture attached*

Sedbober [7]

Answer:

$\sum_{n=3}^{20}(n(n+1))=\sum _{n=3}^{20} n^2+ \sum _{n=3}^{20} n$

Step-by-step explanation:

Given expression : $\sum_{n=3}^{20}(n(n+1))$

Solving further :

$\Rightarrow \sum_{n=3}^{20}(n^2+n)$

$\Rightarrow \sum _{n=3}^{20} n^2+ \sum _{n=3}^{20} n$

So, $\sum_{n=3}^{20}(n(n+1))=\sum _{n=3}^{20} n^2+ \sum _{n=3}^{20} n$

So, The given expression is equivalent to Option A

So, Option A is the answer

7 0

3 years ago

Placing numbers in order

blagie [28]

Answer:

Step-by-step explanation:The largest number is 10,080,000 then 1,224,000 the smallest number is 1,215,678

6 0

3 years ago