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3 years ago

The function h is defined by h(x)=4+3x over 5+x Find h(4z)

Mathematics

1 answer:

Jobisdone [24]3 years ago

5 0

Answer:

h(4z)=4+12z / 5+4z

Step-by-step explanation:

The function h is defined by h(x)=4+3x over 5+x

This can be written as

h(x)=4+3x / 5+x

The value of the function at any time depends on the value of x. x is the independent variable. The variable,x can take any value at any time.

To find h(4z), it means that x is taking the value of 4z.

We will substitute 4z in the place of x in the function. This becomes

h(4z)=4+3×4z / 5+4z

h(4z)=4+12z / 5+4z

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Hector and Francis a spent total of $47.50 at the mall. If Hector spent 50% more than Francis, how much did Francis spend at the

Zigmanuir [339]

Francis spent $19 and Hector spent $28.50

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3 years ago

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There are equal numbers of both red and black cards in a deck of 52.

amid [387]

Answer:

A) there are 13 cards per suit and 4 suits, a total of 52 cards. So there are 13*2=26 red cards in a deck of 13*4=52, the odds of drawing a red card are 26/52=1/2=50%

B) Again outside knowledge is required, you name four suits but not their colors. Nonetheless, unless this is a very unusual deck, the diamonds and hearts are red, spades and clubs black. So that’s 2 red suits out of 4 suits. 2/4=1/2=50%

C) there are 2 black suits and 2 red suits. The odds of getting a red card are 2/(2+2)=2/4=1/2 or 50%

Each of those answers is a different way to figure the odds, they come out the same each time, as expected.

However, what if we assume that you mean… when drawing a 5 card poker hand? Or when Penn Jillette asks you “is this your card?”+ Or if you draw every card in the deck? Or if you are playing some macabre game in which you die if you draw the ace of spades but you may only stop drawing if you draw a red card?

There are myriad possible meanings to your question, I’ve just made the simplest assumption and given the odds on that… but my answer is woefully incomplete.

+ Hint, when Penn Jillette asks you “is this your card” your card is always the 3 of clubs. So… 0% chance.

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4 years ago

In the library at lenape elmentary school, there are 3/8 as, many fiction books as there are nonfiction books. There are 44 book

N76 [4]

Answer:

12 fiction books.

Step-by-step explanation:

Let b represent number of non-fiction books.

We have been given that in the library at Lenape elementary school, there are 3/8 as many fiction books as there are nonfiction books. So number of fiction books would be $\frac{3}{8}x$ .

We are also told that there are 44 books in school library. We can represent this information in an equation as:

$x+\frac{3}{8}x=44$

Let us solve for x.

$\frac{8x}{8}+\frac{3}{8}x=44$

$\frac{8x+3x}{8}=44$

$\frac{11x}{8}=44$

$\frac{11x}{8}\cdot \frac{8}{11}=44\cdot\frac{8}{11}$

$x=4\cdot 8$

$x=32$

Therefore, there are 32 non fiction books in the library.

Number of fiction books would be $\frac{3}{8}x\Rightarrow \frac{3}{8}*32=3*4=12$

Therefore, there are 12 fiction books in the library.

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3 years ago

If you earn $134 in 8 hours, how much do you earn per hour?

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Answer:

1.75

Step-by-step explanation:

because you divided the money you earned by how much time you worked

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3 years ago

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If a single card is drawn from a standard 52-card deck, what is the probability that it is an ace or a spade?

klasskru [66]

A 52-card deck is made up of an equal number of diamonds, hearts, spades, and clubs. Because there are 4 suits, there is a 1/4 chance to draw one of them, in our case, spades.

There are 4 aces in a 52-card deck, so the chance of drawing one is 4/52, or 1/13.

The question asks for the probability of drawing an ace or a spade. Because it uses the word "or," we add the probabilities together. This is because there is a chance of drawing either of the cards; it doesn't have to meet both requirements to satisfy the statement.

However, if the question were to say "and," we would multiply the two probabilities.

Let's add 1/4 and 1/13. First, we can find a common denominator. We can use 52 because both fractions can multiply into it (since the ratio came from a deck of 52 cards as well).

$\frac{1}{4} -- > \frac{13}{52}$

$\frac{1}{13} -- > \frac{4}{52}$

Now we can add them together.

$\frac{13}{52} + \frac{4}{52} = \frac{13+4}{52} = \frac{17}{52}$

This cannot be simplified further, so the probability is 17 in 52, or 33%.

hope this helps!

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2 years ago

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