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3 years ago

If I = PRT/100, MAKE R THE SUBJECT OF THE FORMULA.

Mathematics

1 answer:

Nonamiya [84]3 years ago

6 0

Answer:

R = $\frac{100I}{PT}$

Step-by-step explanation:

I = $\frac{PRT}{100}$ ( multiply both sides by 100 to clear the fraction )

100I = PRT ( isolate R by dividing both sides by PT )

$\frac{100I}{PT}$ = R

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A tank in the form of a right-circular cylinder of radius 2 feet and height 10 feet is standing on end. If the tank is initially

k0ka [10]

Answer:

$\frac{dh}{dt} = -3.48 \times 10^{-3}\sqrt{h}$ feet per second is the differential equation

Step-by-step explanation:

Given:

The radius of the cylindrical tank= 2 feet

The height of the cylindrical tank = 10 feet

The radius of the circular hole = 3/4 inches

To Find:

The differential equation for the height h of the water at time t.

Solution:

Finding the surface area(A) of the tank

Surface area = $\pi R^2$

On substituting the values

Surface area = $\pi(2)^2$

= $4\pi$ square feet

Finding the surface area(a) of the hole

The radius is given in inches, so converting into feet we have

1 inch = 0.083 foot

similarly

$\frac{3}{4} = 0.75 inches = 0.75 \times 0.083$ = 0.0625 feet.

Now the surface area,

= $\pi \times 0.0625$

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Now let the velocity of water through the hole is v

According law of conservation of energy, the penitential energy due to the height h of the water gets converted into kinetic energy.

$\frac{1}{2}mv^2 =mgh$

$v^2 = \frac{2mgh}{m}$

$v^2 = 2gh$

$v= \sqrt{2gh}$

The rate of water flowing through the hole is = $a\times v$

= > $a \times \sqrt{2gh}$

At any time t

$V(t) = A \times h(t)$

$\frac{dV}{dt} = -a\sqrt{2gh}$

$\frac{d(Ah(t))}{dt} = -a\sqrt{2gh}$

$A \frac{d(h(t))}{d(t)} = -a\sqrt{2gh}$

$\frac{dh}{dt} = -\frac{a}{A} \sqrt{2gh}$

On substituting the values, we get

$\frac{dh}{dt} = -\frac{0.0625\pi}{4\pi}\sqrt{2\times 32 \times 10$

$\frac{dh}{dt} = -3.48 \times 10^{-3}\sqrt{h}$ feet per second

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Solve for b. 11 3 b b = [?] Pythagorean Theorem: a2 + b2 = c2 Enter.

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Answer:

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Step-by-step explanation:

a^2+b^2=c^2

3^2+b^2=11^2

9+b^2=121

b^2=121-9

b^2=112

b=√112

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If I = PRT/100, MAKE R THE SUBJECT OF THE FORMULA.​

If I = PRT/100, MAKE R THE SUBJECT OF THE FORMULA.