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3 years ago

1/3 divided by 4 someone help!!

Mathematics

2 answers:

Nesterboy [21]3 years ago

7 0

Answer:

0.08333333333

Step-by-step explanation:

0.08333333333

kozerog [31]3 years ago

6 0

Answer:

1/12

Step-by-step explanation:

1/3 x1/4=1/12

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Can you explain how complex fractions can be used to solve problems involving ratios?

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Example: (1/5)/(4/13)=(1/5)*(13/4)=13/20

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3 years ago

Jenny gave her brother 4 stickers what fraction does she have left

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3 years ago

Read 2 more answers

What ethical issues have been raised by the scientific community's commitment to ensuring that experimental treatments are not

e-lub [12.9K]

Answer:

They include;

1. Fewer chances of determining how effective the treatment plan would be.

2. Inability of every patient to access the experimental treatment.

3. Difficulties in making knowledgeable decisions on the treatment plan.

4. Determining that the experimental treatments are offered with the right motive.

Step-by-step explanation:

In medical treatment administration, it is standard practice that drugs undergo clinical trials on test animals before they are administered to patients. However, some sicknesses are without known drugs for treatment or may have drugs that are still undergoing experiments and trials. In such cases, patients may want to be treated with experimental drugs.

Ethical issues such as the above-listed can arise from this. The foremost of them all is the fact that the treatment might prove ineffective thus causing more problems to the patient.

8 0

3 years ago

Can somebody help me do this?

saveliy_v [14]

Answer:

a) Point Q

b) Sides SQ,RQ

c)Angle RQT and Angle Q

Step-by-step explanation:

6 0

3 years ago

Two machines are used for filling glass bottles with a soft-drink beverage. The filling process have known standard deviations s

stellarik [79]

Answer:

a. We reject the null hypothesis at the significance level of 0.05

b. The p-value is zero for practical applications

c. (-0.0225, -0.0375)

Step-by-step explanation:

Let the bottles from machine 1 be the first population and the bottles from machine 2 be the second population.

Then we have $n_{1} = 25$ , $\bar{x}_{1} = 2.04$ , $\sigma_{1} = 0.010$ and $n_{2} = 20$ , $\bar{x}_{2} = 2.07$ , $\sigma_{2} = 0.015$ . The pooled estimate is given by

$\sigma_{p}^{2} = \frac{(n_{1}-1)\sigma_{1}^{2}+(n_{2}-1)\sigma_{2}^{2}}{n_{1}+n_{2}-2} = \frac{(25-1)(0.010)^{2}+(20-1)(0.015)^{2}}{25+20-2} = 0.0001552$

a. We want to test $H_{0}: \mu_{1}-\mu_{2} = 0$ vs $H_{1}: \mu_{1}-\mu_{2} \neq 0$ (two-tailed alternative).

The test statistic is $T = \frac{\bar{x}_{1} - \bar{x}_{2}-0}{S_{p}\sqrt{1/n_{1}+1/n_{2}}}$ and the observed value is $t_{0} = \frac{2.04 - 2.07}{(0.01246)(0.3)} = -8.0257$ . T has a Student's t distribution with 20 + 25 - 2 = 43 df.

The rejection region is given by RR = {t | t < -2.0167 or t > 2.0167} where -2.0167 and 2.0167 are the 2.5th and 97.5th quantiles of the Student's t distribution with 43 df respectively. Because the observed value $t_{0}$ falls inside RR, we reject the null hypothesis at the significance level of 0.05

b. The p-value for this test is given by $2P(T$ 0 (4.359564e-10) because we have a two-tailed alternative. Here T has a t distribution with 43 df.

c. The 95% confidence interval for the true mean difference is given by (if the samples are independent)

$(\bar{x}_{1}-\bar{x}_{2})\pm t_{0.05/2}s_{p}\sqrt{\frac{1}{25}+\frac{1}{20}}$ , i.e.,

$-0.03\pm t_{0.025}0.012459\sqrt{\frac{1}{25}+\frac{1}{20}}$

where $t_{0.025}$ is the 2.5th quantile of the t distribution with (25+20-2) = 43 degrees of freedom. So

$-0.03\pm(2.0167)(0.012459)(0.3)$ , i.e.,

(-0.0225, -0.0375)

8 0

2 years ago