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RoseWind [281]
2 years ago
5

Which is a factor of 6x2 + x − 7? x + 1 2x + 1 6x + 7 3x + 7

Mathematics
1 answer:
katrin [286]2 years ago
4 0

6x2 + x - 7

= (6x + 7)(x - 1)

So, the answer is (6x + 7), or C.

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8n - (2n+11 - 54)<br>simplify
Serjik [45]

Answer:

8n - (2n + 11 - 54) =

Step-by-step explanation:

6n + 43, I used a calculator !

5 0
2 years ago
There are 3.9 milligrams of calcium in a ½ ounce of cooked chicken. How many milligrams are in 6 ounces?
snow_tiger [21]

Answer:

there are 46.80 milligrams in 6 ounces.

Step-by-step explanation:

3 0
3 years ago
Determine if the following sequence is an Arithmetic Sequence. If it is, what would be the 31st term? NOTE: an=a1+(n-1)d
Ivan
<h3>Key points :-</h3>

᪥ The formula to find the 31st term is : \sf \: a_{n} =  a_{1} + (n - 1) \times d

᪥ In the formula, \sf \: a_{1} represents the first term of the sequence.

᪥ \sf\:n is the number of terms, In our case n is 31.

᪥ \sf\:d is the common difference between the terms, In our case d is 4.

\green{ \rule{300pt}{3pt}}

<em>Detailed Solution is attached</em>᭄

3 0
2 years ago
Read 2 more answers
Jeremy bought a new pair of jeans. The jeans regulary cost $30, but they are on sale for 10 percent off. There is a 6 percent sa
diamong [38]

Step-by-step explanation:

mp=$30

%D=10%=%D=D/M.p×100

10%=D/30$×100=100D=10

DISCOUNT =$3

S.P=$27×6÷100=$1.62+27

<h3> =$28.62</h3>

4 0
3 years ago
If j and k are nonzero integers, which pair of points must lie in the same quadrant?
Marizza181 [45]
<h3>Answer:  Choice D.   (3j, 3k)  and (3/j, 3/k)</h3>

The slash indicates a fraction.

=============================================

Proof:

We'll need to consider 4 different cases.

-----------------------

Case (1): j > 0 and k > 0

If j > 0, then 3j > 0 and 3/j > 0

If k > 0, then 3k > 0 and 3/k > 0

The two points (3j, 3k) and (3/j, 3/k) are both in quadrant 1.

-----------------------

Case (2): j > 0 and k < 0

If j > 0, then 3j > 0 and 3/j > 0

If k < 0, then 3k < 0 and 3/k < 0

Points (3j, 3k) and (3/j, 3/k) are both in quadrant 4.

------------------------

Case (3): j < 0 and k > 0

If j < 0, then 3j < 0 and 3/j < 0

If k > 0, then 3k > 0 and 3/k > 0

Points (3j, 3k) and (3/j, 3/k) are in quadrant 3.

------------------------

Case (4): j < 0 and k < 0

If j < 0, then 3j < 0 and 3/j < 0

If k < 0, then 3k < 0 and 3/k < 0

Points (3j, 3k) and (3/j, 3/k) are in quadrant 4.

------------------------

For nonzero integers j and k, we've shown that Points (3j, 3k) and (3/j, 3/k) are in the same quadrant. This concludes the proof.

8 0
2 years ago
Read 2 more answers
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