Ask question

Ask question

All categories

SCORPION-xisa [38]

3 years ago

8

in a box of 12 fuses, there are 3 that are defective. if a quality control engineer tests 4 of these fuses at random, what is th

e probability that he does not find any of the defective fuses?

1 answer:

vladimir1956 [14]3 years ago

6 0

3/12, or 1/4, are defective.
he tests 4/12, or 1/3, fuses.
1/4(1/3) = 1/12 ?

i’m sorry if this is wrong. i’m not good at probability!

You might be interested in

hichkok12 [17]

Answer:

15. X=23

16.<BCA=59

17. AD=8x-22

18. X=125

7 0

3 years ago

Are the two triangles below similar?

forsale [732]

No would I be your answer, I think it would be number 1! :) hope this helped have a good day!

8 0

2 years ago

Read 2 more answers

5x+6y=18and 18x-15y=36<br> parallel or perpendicular

Katen [24]

Answer:

<u>They</u><u> </u><u>are</u><u> </u><u>neither</u><u> </u><u>parallel</u><u> </u><u>nor</u><u> </u><u>perpendicular</u><u>,</u><u> </u><u>since</u><u> </u><u>slope</u><u> </u><u>are</u><u> </u><u>different</u><u> </u><u>and</u><u> </u><u>not</u><u> </u><u>related</u><u> </u><u>by</u><u> </u><u>any</u><u> </u><u>equation</u>

Step-by-step explanation:

First arrange them according to general equation:

$y = mx + c$

<u>f</u><u>o</u><u>r</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>f</u><u>i</u><u>r</u><u>s</u><u>t</u><u> </u><u>e</u><u>q</u><u>u</u><u>a</u><u>t</u><u>i</u><u>o</u><u>n</u> :

$5x + 6y = 18 \\ 6y = - 5x + 18 \\ { \boxed{y = - \frac{5}{6} x + 3}}$

<u>f</u><u>o</u><u>r</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>s</u><u>e</u><u>c</u><u>o</u><u>n</u><u>d</u><u> </u><u>e</u><u>q</u><u>u</u><u>a</u><u>t</u><u>i</u><u>o</u><u>n</u> :

$18x - 15y = 36 \\ 15y = 18x - 36 \\ y = \frac{18}{15} x - \frac{12}{5}$

8 0

3 years ago

Billy had 55 stamps in his collection. Billy’s older brother Tommy had 73 stamps in his collection. How many stamps did the two

KengaRu [80]

Answer:

128

Step-by-step explanation:

Billy has 55 stamps and his brother Tommy has 73. Add 73 and 55 together. 55+73=128

6 0

2 years ago

please i need help lol The amount of clay students used for their last art project is weighed. The line plot displays the amount

Schach [20]

Answer:

2 1/4

Step-by-step explanation:

We need to see how much clay they used if each person in that group used 3/4 clay. There are 4 people in the group.

=> 3/4 x 4 = 12/4 = 3

Now, we need to see how much clay they used if each person in that group used 1/4 clay. There are 3 people in the group

=> 1/4 x 3 = 3/4

Now, we need to see how much more clay was used.

=>3 - 3/4

=> 3/1 - 3/4

=> Take the LCM of the denominators and make the denominators equal.

=> 12/4 - 3/4

=> 9/4

They used 9/4 more clay.

Since there are no options with 9/4, we need to make this improper fraction into a proper fraction.

=> 9/4 = 2 1/4

They used 2 1/4 more clay.

3 0

3 years ago