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3 years ago

Anyone understand this? If so, pls help a friend out :-)

Mathematics

1 answer:

vivado [14]3 years ago

6 0

Ok, so first we must understand what the slope of a line actually is. The slope, or gradient, is the value by which y increases (or decreases, if this is negative) for each increase of one unit in the x-value. So basically what you should think about for this question is, as x increases, does y decrease, increase or stay the same?

From the graph, we can see that as the value of x gets larger, the value of y also increases, therefor the slope is positive.

For the other answers:

If the slope were negative, we would see that the y-values would get smaller as x would get bigger.

If the slope was zero, you would see a horizontal line; this means that there is no change in the y-value as x-increases.

If the slope was undefined, you would see a vertical line; this is an extreme case where you cannot say how much y increases by as the line continues till infinity, therefor we say that it is undefined.

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A car is traveling at a speed of 30 meters per second. What is the car's speed in kilometers per hour? How many kilometers will

vitfil [10]

Answer:

216,000

Step-by-step explanation:

3 0

2 years ago

Find the exact values of a) sec of theta b)tan of theta if cos of theta= -4/5 and sin<0

Gre4nikov [31]

Answer:

Using trigonometric ratio:

$\sec \theta = \frac{1}{\cos \theta}$

$\tan \theta = \frac{\sin \theta}{\cos \theta}$

From the given statement:

$\cos \theta = -\frac{4}{5}$ and sin < 0

⇒ $\theta$ lies in the 3rd quadrant.

then;

$\sec \theta = \frac{1}{-\frac{4}{5}} = -\frac{5}{4}$

Using trigonometry identities:

$\sin \theta = \pm \sqrt{1-\cos^2 \theta}$

Substitute the given values we have;

$\sin \theta = \pm\sqrt{1-(\frac{-4}{5})^2 } =\pm\sqrt{1-\frac{16}{25}} =\pm\sqrt{\frac{25-16}{25}} =\pm \sqrt{\frac{9}{25} } = \pm\frac{3}{5}$

Since, sin < 0

⇒ $\sin \theta = -\frac{3}{5}$

now, find $\tan \theta$ :

$\tan \theta = \frac{\sin \theta}{\cos \theta}$

Substitute the given values we have;

$\tan \theta = \frac{-\frac{3}{5} }{-\frac{4}{5} } = \frac{3}{5}\times \frac{5}{4} = \frac{3}{4}$

Therefore, the exact value of:

(a)

$\sec \theta =-\frac{5}{4}$

(b)

$\tan \theta= \frac{3}{4}$

7 0

3 years ago

(no links please and than you! :))

pashok25 [27]

Answer:

Line D represents a proportional relationship.

Step-by-step explanation:

In an easy way to explain what a proportional relationship is, it is basically a line graph that passes through the origin point. When a line graph passes through the origin point (0,0), it is proportional.

Other graphs do not intersect the origin points so they are not proportional.

6 0

3 years ago

Read 2 more answers

Please help!! The slope of the line passing through the points (-3, 4) and (4, -1) is ___.

oksano4ka [1.4K]

I hope this helps you

slope=m

(-3,4) x'=-3 y'=4

(4,-1) x"=4 y"=-1

slope formula :

m. (x'-x")=y'-y"

m. (-3-4)=4-(-1)

m.-7=4+1

m=-5/7

4 0

3 years ago

(1CQ) Determine whether the series -8/5+32/25-128/125+... is convergent or divergent.

Ivan

Answer:

The series is convergent answer ⇒ (a)

Step-by-step explanation:

* The series is -8/5 + 32/25 + -128/125 + ........

- It is a geometric series with:

- first term a = -8/5 and common ratio r = 32/25 ÷ -8/5 = -4/5

* The difference between the convergent and divergent

in the geometric series is :

- If the geometric series is given by sum = a + a r + a r² + a r³ + ...

* Where a is the first term and r is the common ratio

* If |r| < 1 then the following geometric series converges to a / (1 - r).

- Where a/1 - r is the sum to infinity

* The proof is:

∵ S = a(1 - r^n)/(1 - r) ⇒ when IrI < 1 and n very large number

∴ r^n approach to zero

∴ S = a(1 - 0)/(1 - r) = a/(1 - r)

∴ S∞ = a/1 - r

* If |r| ≥ 1 then the above geometric series diverges

∵ r = -4/5

∴ IrI = 4/5

∴ IrI < 1

∴ The series is convergent

3 0

3 years ago