Y = e^tanx - 2
To find at which point it crosses x axis we state that y= 0
e^tanx - 2 = 0
e^tanx = 2
tanx = ln 2
tanx = 0.69314
x = 0.6061
to find slope at that point first we need to find first derivative of funtion y.
y' = (e^tanx)*1/cos^2(x)
now we express x = 0.6061 in y' and we get:
y' = k = 2,9599
Answer:
.02
Step-by-step explanation:
Answer:
Angle 1 = 46°
Angle 2 = 44°
Step-by-step explanation:
Given:
Angle 1 = (4x - 2)°
Angle 2 = (3x + 8)°
Angle 3 = 90°
Find:
All acute angle
Computation:
Using angle sum property
Angle 1 + Angle 1 + Angle 1 = 180°
(4x - 2)° + (3x + 8)° + 90° = 180°
7x + 6 = 90
7x = 84
x = 12°
So,
Angle 1 = (4x - 2)° = 4(12) - 2 = 46°
Angle 2 = (3x + 8)° = 3(12) + 8 = 44°
If you mean average, then it's quite simple.
Usually when you want to find the average of something, you add them up all together and divide by how many there are.
For example, the numbers:
12, 69, 35, 67, and 2.
Steps:
1.) Add them. 12 + 69 + 35 + 67 + 2 = 185
2.) 185 divided by 5.
3.) Answer: 37
Answer:
2 meters.
Step-by-step explanation:
Just trust me. Khan Academy answer.
