Answer:
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I can do algebra forever</u></h2>
First we can use distributive property. 2a-10 = 6. So we add 10 on both sides and get 2a=16. Then we divide both sides by 2 so we get a = 8. Therefore proved algebraically that a = 8. I can always do algebra. Feel free to keep asking questions like these. Well feel free to ask any question because this is brainly.
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Answer is a = 8, 8 is answer</u></h2><h2><u>
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<u>brainliest</u>
a. The expression y=5x represent the number of small marbles she has.
b. The expression z=3x+2 represents the number of large marbles she has.
c. Amy has 310 small marbles, 62 medium marbles and 188 large marbles.
Step-by-step explanation:
a. Let x represent the number of medium marbles Amy has. Write an algebraic expression to represent the number of small marbles she has.
Medium marbles = x
Let,
Small marbles = y
According to given statement;
She has five times as many small marbles as medium marbles.
y = 5x Eqn 1
The expression y=5x represent the number of small marbles she has.
b. Write an algebraic expression to represent the number of large marbles she has.
Let,
Large marbles = z
The number of large marbles is two more than three times the number of medium marbles.
z = 3x+2 Eqn 2
The expression z=3x+2 represents the number of large marbles she has.
c. If Amy has a total of 560 marbles, how many of each size does she have?
x+y+z= 560 Eqn 3
Putting value of y and z from Eqn 1 and 2 in Eqn 3

Dividing both sides by 9

Putting x=62 in Eqn 1

Putting x=62 in Eqn 2

Amy has 310 small marbles, 62 medium marbles and 188 large marbles.
Keywords: linear equation, substitution method
Learn more about substitution method at:
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Answer
x≤3/17 or x≥-10
Step-by-step explanation:
Step-by-step explanation:
Consider LHS

Apply quotient identies

Multiply the fraction and sine.

Make cos x a fraction with cos x as it denominator.

so

Pythagorean Identity tells us sin squared and cos squared equals 1 so

Apply reciprocal identity.

The answer is three significant figures. The 1 and the 7 are both significant, because they are non-zero quantities.
This is where significant figures gets a little more complicated, because if a zero is used as a placeholder (i.e. 0.00027 cm) then it is insignificant.
But in the case above, the zero isn't being used as a placeholder, and thus, is significant.