Answer:
A customer who sends 78 messages per day would be at 99.38th percentile.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean and standard deviation , the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Average of 48 texts per day with a standard deviation of 12.
This means that
a. A customer who sends 78 messages per day would correspond to what percentile?
The percentile is the p-value of Z when X = 78. So
has a p-value of 0.9938.
0.9938*100% = 99.38%.
A customer who sends 78 messages per day would be at 99.38th percentile.
He was there for 4 hours and plus the 50 that be $350 i don’t know how to write the equation hope this helps
The answer is 9w you use normal addition because the unknown are all the same
(-1,5)(2,4)
slope = (4 - 5) / (2 - (-1) = -1/3
y = mx + b
slope(m) = -1/3
use either of ur points (2,4)...x = 2 and y = 4
now sub and find b, the y int
4 = -1/3(2) + b
4 = -2/3 + b
4 + 2/3 = b
12/3 + 2/3 = b
14/3 = b
so ur equation is : y = -1/3x + 14/3....however, this is not ur answer because it is not in standard form.
y = -1/3x + 14/3
1/3x + y = 14/3....multiply both sides by 3
x + 3y = 14 <=== standard form