All categories

4 years ago

Divide these polynomials (8x^3+2x^2-7x+2)/(2x-1)

Mathematics

1 answer:

dedylja [7]4 years ago

3 0

Answer:

$4x^2+3x-2$

Step-by-step explanation:

We are given that

$\frac{8x^3+2x^2-7x+2}{2x-1}$

We have to divide the polynomials.

We have

Divisor polynomial= $2x-1$

Dividend polynomial= $8x^3+2x^2-7x+2$

$\frac{8x^3+2x^2-7x+2}{2x-1}=4x^2+3x-2$

Quotient= $4x^2+3x-2$

Remainder=0

You might be interested in

Rewrite the expression from part B using the additive inverse that you identified in part C.

Naya [18.7K]

Answer:

12.3 – (-9.6) = 12.3 + 9.6

Step-by-step explanation:

4 0

3 years ago

PLS HELP ASAP. IM TIMED

Xelga [282]

Answer:

Choice 3

Step-by-step explanation:

Using V = πr^2 h

Choice 1. π2^2x6 = 75.4

Choice 2. π2.5^2x5 = 98.17

Choice 3. π3^2x4 = 113.1

Choice 4. π3.2^2x3 = 96.51

4 0

3 years ago

Dogs are inbred for such desirable characteristics as blue eye color, but an unfortunate by-product of such inbreeding can be th

sesenic [268]

Answer:

The probability that the dogs are blue eyed and deaf is 13.02%.

Step-by-step explanation:

We are given the following information in the question:

P(Blue eyes) = 31%

P(Deaf) = 38%

P(Deaf | Blue eyes) = 42%

Formula for conditional probability:

$P( A|B) = \displaystyle\frac{P(A \cap B)}{P(B)}$

Now, let A be the event where the dog is deaf and B be the the event where dog is blue eyed.

$P( \text{ Deaf}|\text{Blue eyes}) = \displaystyle\frac{P( \text{Deaf} \cap \text{Blue eyes})}{P(\text{Blue eyes})}\\\\0.42 = \displaystyle\frac{P( \text{Deaf} \cap \text{Blue eyes})}{0.31}\\\\P( \text{Deaf} \cap \text{Blue eyes}) = 0.42\times 0.31 = 0.1302 = 13.02\%$