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3 years ago

When a figure is translated, its orientation (blank) and the measures of its angles (blank).

Mathematics

2 answers:

3241004551 [841]3 years ago

8 0

Answer:

Its orientation may change and the measures of its angles stay the same.

Step-by-step explanation:

marin [14]3 years ago

7 0

Answer:

When a figure is translated its orientation may change and the measures of its angles keeps the same measure.

Step-by-step explanation:

Whenever we translate a figure, we move a figure into some orientation given by this same vector. But the angles will remain the same since there is no distortion.

Just as the picture below

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Find the vertex, the equation and axis of symmetry, and the y-intercept of the graph of y=2x^2-8x+6

o-na [289]

Answer:

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Step-by-step explanation:

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3 years ago

Total mass vs. numbers of cd and numbers of cd

Gekata [30.6K]

Answer: Choice A) M = 0.25n + 100

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Explanation:

For now, I'll treat n as x, and M as y.

In other words,

x = number of CDs
y = total mass in kg

Let's select two points from this graph. I'll pick (200,150) and (400,200)

The slope of the line through those points is

m = (y2-y1)/(x2-x1)

m = (200-150)/(400-200)

m = 50/200

m = 0.25

Now we'll use the point (x,y) = (200,150) along with that slope value to find the y intercept b

y = mx+b

150 = 0.25*200+b

150 = 50+b

150-50 = b

100 = b

b = 100

You could also use (x,y) = (400,200) and you should get the same b value.

In fact, any other point from this graph works as well.

------------------------------

Since m = 0.25 and b = 100, we go from y = mx+b to y = 0.25x+100

This then translates over to M = 0.25n + 100 which is choice A

To help verify this, let's say we plugged in n = 100

M = 0.25*n + 100

M = 0.25*100 + 100

M = 25 + 100

M = 125

Which is confirmed by what the graph shows. I'll let you check the other points as well.

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A function normally tells you what y is if you know what x is. The inverse of a function will tell you what x had to be to get that value of y.

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The domain of f is the range of f -1 and the range of f is the domain of f -1.

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