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Mnenie [13.5K]
3 years ago
10

Hellpp mee plzzz anyonee

Mathematics
1 answer:
kozerog [31]3 years ago
4 0
On the first one you add the first 2 numbers then subtract that from 7 1/2
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Pls just say how to find the right graph of the function
ElenaW [278]

The period of an function, is how many times it takes to complete one cycle, if the period is 2π then after 2π the function would have been completed one entire cycle, but what I mean by cycle?

It's when the function start again, these functions are called periodic functions for a reason, after between that interval, the function goes up, goes to 0 again, go down and finally goes zero again, it means a cycle! the function goes up, down and then return to the same point.

If you look at the picture, the function took 2π just to go up and zero, it needs more 2π to go down and return to zero, then it's period is 4π.

The bottom function complete its cycle in just π!

I hope you liked it, maybe the draw will help you!

Any doubt? just write in the comment and I'll help you.

4 0
3 years ago
Complete the table by providing justification for each step of the proof. Conjecture: If 4(x2 – 2) = 28, then x is 3 or –3
Anika [276]
<span>4(x2 – 2) = 28
4x^2-8=28 Distributive law of multiplication

4x^2+8=28+8 Additive identity
4x^2=36 ; adding 8 to both sides
x^2 =9, dividing both sides by 4
x= +/- 3</span>
5 0
4 years ago
A p-value of .06 is a significant finding. true or false
Mariulka [41]
Its true .


A p-value less than 0.05 (typically ≤ 0.05) is statistically significant. It indicates strong evidence against the null hypothesis, as there is less than a 5% probability the null is correct
8 0
3 years ago
Read 2 more answers
Describe the parts of this algebraic expression using the lesson’s vocabulary. Negative x + 10.2 minus one-half x + y
olya-2409 [2.1K]

The equation would be -x+10.2-\frac{1}{2}x+y

The equation contains:

-decimals

-variables

-negatives

-fractions

-like-terms

7 0
3 years ago
Which is the first step needed to solve by substitution?
fredd [130]
\begin{gathered} -x+y=-1 \\ 2x-y=3 \end{gathered}

To solve the given system of equations for substitution you:

1. Solve in one of the equations a variable.

For the given options the one that is correct is solve the first equation for y, by adding x to both sides:

\begin{gathered} -x+x+y=-1+x \\ y=-1+x \end{gathered}

4 0
2 years ago
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