Answer:
Step-by-step explanation:
For a given function f(x), we define the domain as the set of the possible inputs of the function and the range as the set of the outputs of the function.
We will see that both domain and range are the set of all real numbers.
D = (-∞, ∞)
R = (-∞, ∞)
Here we have the function:
The first thing we need to do is find the domain.
We start by assuming that the domain is the set of all real numbers and then we try to find some given values of x that cause some undefined operation, and then we remove these values of x from the domain.
Where this would be something like a zero in the denominator or something like that. We also could have specific restrictions to the domain that are applied in some specific cases (for example if x represents a length we should remove the negative values from the domain).
Here we can see that we do not have any indetermination, thus the domain is the set of all real numbers.
Now to study the range we need to see the general function, we can see that as x tends to negative infinity y will also tend to negative infinity, while when x tends to infinity y will also tend to infinity.
Then the range will also be the set of all real numbers.
<span>The partial derivative of the given function with respect to x is
a - by/cx2 + dy/dx
In this derivative the terms in the with x is only considered other or treated as constant
The partial derivative of the given function with respect to y is
b/cx+ d2y/dx.
In this derivative the terms in the with x is only considered other or treated as constant</span>
Answer:
Part A: x^2 + 6x + 8 = 0 use the factoring the equation method
Part A: x^2 + 6x + 8 = 0 use the quadratic formula
Step-by-step explanation:
Part A;
The equation is x^2 + 6x + 8 = 0 , looking at this quadratic expression, you notice it is written in a quadratic equation standard form of ax^2+bx+c=0. Additionally, you notice that can find what multiplied to get the quadratic equation,factor.You can identify two numbers that multiply to get ac and add to give b.In this question;
a=1,b=6,c=8
ac=8
The numbers are 4 and 2. Factoring the equation method will give;
x²+6x+8=0
x²+4x+2x+8=0
x(x+4)+2(x+4)=0
(x+2)+(x+4)=x²+6x+8
x+2=0, x=-2 and x+4=0, x=-4
Part B
The quadratic equation is ;
x²+6x-11=0
You notice that there are no factors that multiply direct to get the quadratic equation like in part 1. When you observe, a=1, b=6 and c=-11
ac=1×-11=-11 and b=6 .You notice there are no factors that multiply to give -11 and add to get 6, hence the factorizing the equation method can not be used.However, you can apply the quadratic formula that requires coefficients. You have a=1, b=c and c=-11 as the coefficients to use in the quadratic formula.
Answer:
x>-2
Step-by-step explanation:
First you have to subtract 2 from both sides, which leaves you with -3x=6, then you have to divide -3 on both sides to get the variable by itself. Which is x<-2, but you have to switch the sign because you multiplied/divided by a negative number, then you get left with x>-2........Hope that helped!!!!!!!!!!:)
Hey there! :)
Answer:
f(-2) = 2.
Step-by-step explanation:
To find f(-2), we simply need to look at the y value at x = -2.
At x = -2, the y value is equal to 2.
Therefore:
f(-2) = 2.
