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Gekata [30.6K]
4 years ago
14

What is quartile 1 (Q1)quartile 3 (Q3) and the IQR? Answer all three parts . 13, 23, 24, 25, 26, 26, 37, 47, 47, 48, 50

Mathematics
1 answer:
Fittoniya [83]4 years ago
7 0

Answer:

Quartile 1 (Q1) = 24

Quartile 2 (Q2) = 47

IQR = 23

Step-by-step explanation:

Given:

The set of data are:

13, 23, 24, 25, 26, <u>26</u>, 37, 47, 47, 48, 50

The data are in increasing order. The number terms are, n = 11.

Therefore, the middle term = \frac{n+1}{2}=\frac{11+1}{2}=6^{th}\ term

So, the median = 26

Now, the median divides the set of data into two parts. The median of first part is the quartile 1 and the median of second part is quartile 2.

So, the first part has the following terms:

13, 23, <u>24</u>, 25, 26

Here also, n=5. So, the third term is the median.

∴ Q1 = 24

The second part has the following terms:

37, 47, <u>47</u>, 48, 50

Here also, n=5. So, the third term is the median.

∴ Q2 = 47.

Now, IQR = Q2 - Q1 = 47 - 24 = 23.

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Sara hina and Arslan have a total of RS 390in their wallet . Sara has Rs. 7more than Hina .Arslan has 3 times what sara has . Ho
Brums [2.3K]

Answer:Sara hina and Arslan Have RS79.4,RS 72.4 and RS238.2 respectively.

Step-by-step explanation:

Step 1

Let the amount that hina has be x

the amount that sara has be represented as  7+x

and the amount that Arslan have be represented as 3(7+x)

such that the total amount in their wallet which is 390 can be expressed as

x+7+x + 3(7+x)=390

Step 2

Solving

x+7+x +21+3x=390

5x+28=390

5x==390-28

x=362/5=72.4

Hina has RS 72.4

Sara =7+x==72.4+77= RS 79.4

Arslan =3(7+x)=3 x 79.4=RS 238.2

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