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Alexeev081 [22]
3 years ago
5

I’ll give Brainly for helping

Mathematics
2 answers:
dmitriy555 [2]3 years ago
8 0
The answer is 16 so it is B
Vanyuwa [196]3 years ago
7 0

Answer: 16

Step-by-step explanation:

You might be interested in
Can someone please help and please show work
pychu [463]

Answer:


Step-by-step explanation:

4 and a half

8 0
3 years ago
In 1875 an estimated twelve-and-a-half trillion locusts appeared in Nebraska.Write the number of locusts in scientific notation.
oksano4ka [1.4K]

Answer:

12.5 x 10^12

Step-by-step explanation:

12,500,000,000,000

12 zeroes following 12.5

3 0
3 years ago
1. <br>Solve the quadratic equation using quadratic formula :<br><br>x2 – 7x + 12 = 0​
frez [133]

Answer:

x = 4 and 3

Step-by-step explanation:

[7±√(-7)²-4(1)(12)]/2

x = 4, 3

3 0
3 years ago
A portion of the graph of f(x) = −x2 − 2x + 8 is shown. Which of the following describes all solutions for f(x)?
Naily [24]

Answer:

(x,-x^2-2x+8) where −5 ≤ x ≤ 3

Step-by-step explanation:

The given function is f(x)=-x^2-2x+8.

We want to select the option that describes all the solutions to the parabola.

The domain of the parabola is −5 ≤ x ≤ 3.

This means that  any x=a on −5 ≤ x ≤ 3 that satisfies (a,f(a)), is a solution.

This can be rewritten as (a,-a^2-2a+8)

Therefore for x belonging to −5 ≤ x ≤ 3, all solutions are given by:

(x,-x^2-2x+8) where −5 ≤ x ≤ 3.

7 0
4 years ago
Kenny had 5/7 more trading cards than lee. After Kenny collected 50% more trading cards, he had 220 more trading cards than lee.
svp [43]

Answer:

Step-by-step explanation:

Let X is the number of cards Kenny has

Let Y is the number of cards Lee has

1. Kenny had 5/7 more trading cards than lee, it means

X = Y + 5/7X (1)

2. After Kenny collected 50% more trading cards, he had 220 more trading cards than lee, it means:

X + 50%X = Y +  220 (2)

So, we solve the 2 equations to find out X and Y

\left \{ {{X=Y + 5/7X} \atop {1.5X=Y +220}} \right.

<=> X = \frac{3080}{17} and Y = \frac{880}{17}

<=> X ≈181 and Y ≈ 52

6 0
3 years ago
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