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spin [16.1K]
3 years ago
5

Write as a Improper fraction

Mathematics
2 answers:
Likurg_2 [28]3 years ago
8 0
38/9
46/7
44/5
11/4
19/2
11/6
23/3
41/8
52/7
34/5
Harrizon [31]3 years ago
7 0

Answer:

38/9

46/7

44/5

11/4

19/2

11/6

23/3

41/8

52/7

34/5

Step-by-step explanation:

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What is the Factor of 4х2 - 100
Elis [28]

Answer: The factors of 100.

1,2,4,5,10,20,25,50,100,

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3 years ago
Find the total cost with tip.
SpyIntel [72]

Answer:

$147

Step-by-step explanation:

so to find 20% I usually divide the original cost by 100 to get 1% then multiply that number by 20.

in this case 122.50/100= 1.225, 1.225x20 = 24.5

24.5 + 122.50 = 147

5 0
2 years ago
26. Students who take a statistics course are given a pre-test on the concepts and skills for the first chapter of a statistics
hjlf

The test statistic value lies to the right of the critical value. So we have sufficient evidence to reject the null hypothesis.

<h3>What are null hypotheses and alternative hypotheses?</h3>

In null hypotheses, there is no relationship between the two phenomenons under the assumption or it is not associated with the group. And in alternative hypotheses, there is a relationship between the two chosen unknowns.

Students who take a statistics course are given a pre-test on the concepts and skills for the first chapter of a statistics course.

Then they are given a post-test once the professor has concluded lecturing on the material.

Pre-test and post-test scores for 4 students in an elementary statistics class are given below.

Then we have

\mu _d = \mu _{post} - \mu _{pre}

Then the null hypotheses and alternative hypotheses will be

H₀: \mu _d = 0

Hₐ: \mu _d > 0

Then the test statistic will be

\rm \overline{x} _d = \dfrac{\Sigma x_d}{n} = \dfrac{15+12+10+1}{4}\\\\\overline{x} _d = 9.5

Then

\rm S_d = 6.02

The test statistic value is given by

\rm t = \dfrac{\overline{x} _d }{\dfrac{S_d}{\sqrtn}} \\\\t = \dfrac{9.5}{\dfrac{6.02}{\sqrt4}}\\\\t = 3.16

Since this is a right-tailed test, so the critical value is given by

\rm t_{n-1}(\alpha ) = t_3 (0.05) = 2.353

Since the test statistic value lies to the right of the critical value. So we have sufficient evidence to reject the null hypothesis.

Hence, we can conclude that \mu _d > 0 that is test scores have improved.

More about the null hypotheses and alternative hypotheses link is given below.

brainly.com/question/9504281

#SPJ1

7 0
2 years ago
Factor by grouping 20p³+15p²+24p+18​
ivolga24 [154]
(4p +3)(5p2 + 6) is your answer
7 0
3 years ago
Please help!! whoever gets right i’ll mark brainlist
storchak [24]

Answer:

It's B

Step-by-step explanation:

Because 10 less than 20 mean 20 is not greater so B. ) is correct

3 0
3 years ago
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