What type of natural selection was acting on the lab scenario

1 answer:

4 0

Types of natural selection: Different types of natural selection can impact the distribution of phenotypes within a population.In (a) stabilizing selection, an average phenotype is favored.In (b) directional selection, a change in the environment shifts the spectrum of phenotypes observed.In (c) diversifyingselection.

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What part of the cell defines cell shape?

pochemuha

<span>Defines cell shape= </span><span>cytoskeleton

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6 0

3 years ago

An average number of eggs a bird lays is based on natural selection. If a bird lays too many eggs, there a high chance that she

mr_godi [17]

The correct answer is stabilizing selection.

Stabilizing selection is a kind of natural selection in which the mean of the population steadies on a specific non-extreme trait value. This is considered to be the most general process of action for natural selection as the majority of the traits do not seem to vary radically with time.

Stabilizing selection is the reverse of disruptive selection. In spite of preferring individuals with extreme phenotypes, it favors the transitional variants. Stabilizing selection seems to eradicate the more extreme phenotypes, resulting in the reproductive success of the average or norm phenotypes.

This signifies that the most general phenotype in the population is chosen and continues to govern in the coming generations. As the majority of the traits vary slightly with time, stabilizing selection is considered to be the most usual kind of selection in the majority of the populations.

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3 years ago

Newsweek in 1989 reported that 60% of young children have blood lead levels that could impair their neurological development. As

Kamila [148]

Answer:

The answer is 83.38%.

Explanation:

The probability of young children having blood levels that impair their neurological development is given as 60% in the question. To find the probability of at least 5 children out of 10 in a sample having said blood levels, we need to use the binomial probability.

n represents the total number of children in the sample so n = 10 and p is the probability of the children having blood levels causing the problem which is 60% so p = 0.6.

We want the probability of it being observed for 5 or more children and that is $P(x\geq 5)$ . If we subtract the $P( x\leq 4)$ from 1, which is the probability of not observing the condition in 5 or more children, we will have the $P(x\geq 5)$ .

$1 - P(x\leq 4) = 1 - pbinom(4, 10, 0.6)$ which are the probability range in the function, the sample size and the probability of observing the condition respectively.